Given :
The foci of hyperbola are (8,0) and (-8,0) .
The difference of the focal radii = 6.
To Find :
The equation of the hyperbola.
Solution :
We know, distance between foci is given by :
2c = 8 - (-8)
c = 8
Also, difference between the foci or focal distance is given by :
2a = 6
a = 3
Now, we know for hyperbola :

General equation of hyperbola is :

Hence, this is the required solution.
Answer:
i think its D
f(x) = x-3 and g(x) = x+11
f(x) *g(x) = (x-3)(x+11) = x^2 +11x -3x -33 = x^2 +8x -33
hope this helped :3
Answer:
y = x/4 -1/2
Step-by-step explanation:
given coordinates : ( -2, -1 ) and ( 2 , 0 )
gradient = y2 - y1 / x2 - x1
= 0 - -1 / 2 - -2
= 1/4
equation of line:
y - y1 = m( x - x1 )
y - 0 = 1/4 ( x - 2 )
y = x/4 -1/2
the line shown below to confirm:
Answer:
C.
Step-by-step explanation:
0=40-10t-5t^2
t^2+2t-8=0
(t+4)(t-2)=0
t=-4 (not a solution) or t=2
Answer: after 2 seconds