At 3 p.m the temperature was 9°f by 11 pm it had dropped 31°f what was the temperature at 11 pm

A pathologist knows that 14.9% of all deaths are attributable to myocardial infarctions (a type of heart disease). (Either you h

garik1379 [7]

Answer:

a) The mean number is 745 and the standard deviation is 25.18.

b) 896 deaths is a significantly high number, which means that there is cause for concern.

Step-by-step explanation:

For each death, there are only two possible outcomes. Either it is attributable to myocardial infarctions, or it is not. The probability of a death being attributable to myocardial infarctions is independent of other deaths. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

A value X is significantly high is:

$X > E(X) + 2\sqrt{V(X)}$

In this problem:

$p = 0.149, n = 5000$

a. Find the mean and standard deviation for the number of such deaths that will occur in typical region with 5000 deaths.

$E(X) = np = 5000*0.149 = 745$

$\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{5000*0.149*0.851} = 25.18$

The mean number is 745 and the standard deviation is 25.18.

b. In one region, 5000 death certificates are examined, and it is found that 896 deaths were attributable to myocardial infarction. Is there cause for concern? Why or why not?

Is 896 a significantly high number?

$E(X) + 2\sqrt{V(X)} = 745 + 2*25.18 = 795.36$

895 > 795.36

896 deaths is a significantly high number, which means that there is cause for concern.

6 0

3 years ago

Mr. and Mrs. Romero are expecting triplets. Suppose the chance of each child being a boy is 50% and of being a girl i 50% . find

Bingel [31]

Pr(1/2) for both I believe. If not right sorry.

5 0

3 years ago

162 water bottles in 9 cases

sveta [45]

162/9=18 in each case

4 0

3 years ago

A campus program evenly enrolls undergraduate and graduate students. If a random sample of 5 students is selected from the progr

Bezzdna [24]

Answer:

The answer is "0.03125".

Step-by-step explanation:

Two types of undergraduates exist. Its chance for selecting the very first person who is part of degree studies will be 1/2. The probability will also be 1/2 for the 2nd person, as well as, the 3rd, 4th, and 5th person. For 5 random samples, the probability of the graduate therefore is

$\to \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} = \frac{1}{32}=0.03125$

4 0

3 years ago

The continuous function f is defined on the interval -4 ≤ x ≤ 3. there is no point c, -4 ≤ c ≤ 3, for which

zalisa [80]

We can say that there is no point c, which is not defined on this function's domain. Indeed, the intervals of this function and the interval of c coincide.

8 0

3 years ago