Answer:
D. He forgot to subtract the area of the base from the total surface area of the cube.
Step-by-step explanation:
He is only spray washing the *exterior* of the building; the base is not exposed so it will not be spray washed, which means Richard can use less water.
Hope this helps. :)
The random probability of event X, wheel stopping on a white slice is 0.9 while the probability of not X, wheel stopping on Grey slice is 0.1
- Total numbers on wheel = total possible outcomes = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}
- Grey colored portion = {3}
- White colored portion = {1, 2, 4, 5, 6, 7, 8, 9, 10}
- X = Event that wheel stops on a white slice
- P(X) = number of white slices ÷ total number of slices
Therefore, the probability that wheel stops on a white slice is 0.9 while, the probability that wheel does not stop on a white slice is 0.1
Learn more :brainly.com/question/18153040
Answer:
<u>Given</u>
- tanθ = 3.454
- θ is in the III quadrant
We know in the III quadrant both sine and cosine are negative.
<u>Use the following identities to get values of sinθ and cos θ</u>
- sinθ = - tanθ/√(1 +tan²θ)
- cosθ = - 1/√(1 +tan²θ)
<u>Substitute the value of tanθ and find sine and cosine:</u>
- sinθ = - 3.454/√(1 + 3.454²) = - 0.961
- cosθ = - 1/√(1 + 3.454²) = - 0.278
Answer:
pls like and make me brainliest :)
Step-by-step explanation:
1275 divided by 15=$85 each
Answer:
Step-by-step explanation:
Given the expression cosec (x) = 4 and tan(x)< 0
since cosec x = 1/sinx
1/sinx = 4
sinx = 1/4
From SOH, CAH TOA
sinθ = opposite/hypotenuse
from sinx = 1/4
opposite = 1 and hypotenuse = 4
to get the adjacent, we will use the Pythagoras theorem
adj² = 4²-1²
adj² = 16-1
adj ²= 15
adj = √15
cosx = adj/hyp = √15/4
tanx = opposite/adjacent = 1/√15
since tan < 0, then tanx = -1/√15
From double angle formula;
sin2x = 2sinxcosx
sin2x = 2(1/4)(√15/4)
sin2x = 2√15/16
sin2x = √15/8
for cos2x;
cos2x = 1-2sin²x
cos2x = 1-2(1/4)²
cos2x = 1-2(1/16)
cos2x= 1-1/8
cos2x = 7/8
for tan2x;
tan2x = tanx + tanx/1-tan²x
tan2x = 2tanx/1-tan²x
tan2x = 2(-1/√15)/1-(-1/√15)²
tan2x = (-2/√15)/(1-1/15)
tan2x = (-2/√15)/(14/15)
tan2x = -2/√15 * 15/14
tan2x = -30/14√15
tan2x = -30/7√15
rationalize
tan2x = -30/7√15 * √15/√15
tan2x = -30√15/7*15
tan2x = -2√15/7
