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lesya692 [45]
3 years ago
5

An auto service center that specializes in oil changes has two service bays that serve, on average, a total of 24 cars per eight

-hour business day. On average, each bay can finish one oil change in 30 minutes.
What is the design capacity? 30 min per oil change per bay (8 hr day x 2 (30 min each) =16 x 2 bays =?)
Mathematics
1 answer:
inysia [295]3 years ago
7 0

Answer:

32

Step-by-step explanation:

Given

Number of service bays = 2

Time taken by each bay to finish one oil change = 30 minutes

Working capacity = 8 hours per day

Thus, in 8 hours the total number of times one bay has changed the oil is equal to

\frac{8 * 2 * 30}{30} \\= 16

If one service bay's capacity is equal to 16, capacity of two service bays is equal to

16 * 2 \\= 32

Thus, the design capacity is 32

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X = -6y - 12
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x = -6y - 12
x = -6(-3) - 12
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4 years ago
Please help its urgent
ankoles [38]

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Step-by-step explanation:

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3 years ago
5 divided by 485 3 digit by 1 digit
victus00 [196]

Answer:

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Step-by-step explanation:

When we say "a divided by b", we mean a/b. In this case, "5 divided by 485" is a 1-digit number divided by a 3-digit number. The result is the fraction 1/97 or a repeating decimal with a long repeat.

If you want to divide the 3-digit number 485 by the 1 digit number 5, then you need to formulate the problem as "485 divided by 5". The result is 97.

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3<img src="https://tex.z-dn.net/?f=%5Csqrt%7B16%7D" id="TexFormula1" title="\sqrt{16}" alt="\sqrt{16}" align="absmiddle" class="
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Answer:

Step-by-step explanation:

hello :

let: A = 3√16+√-9

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