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3 years ago

ANSWER PLS ASAP

Mathematics

2 answers:

iren [92.7K]3 years ago

7 0

if the tins are shown like this:

TIN A: 2:3

TIN B: 4:5

TIN A: can also be shown as 4:6

there for theirs is more blue in the first tin then second tin

tekilochka [14]3 years ago

7 0

The proportion of blue in Tin A is 3 / (3+2) = 3/5 = 0.6

In Tin B proportion of blue = 5/ (5+4) = 5/9= 0.56

So Tin A has the greatest proportion of blue.

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The perimeter of a rectangular field is 328 yards. If the length of the field is 89 yards, what is its width?

miv72 [106K]

Set up an equation based on the information given

$89 + 89 + x + x = 328$

Combine like terms

$89 + 89 = 178$

$x + x = 2x$

$2x + 178 = 328$

Solve

$2x + 178 = 328$

$328 - 178 = 150$

$2x = 150$

$x = 75$

Answer

The width of the rectangular field is 75 yards.

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3 years ago

Find the greates common factor of the following monomials:2r^4s^2 and 36r^4s^3

ki77a [65]

The greatest common factor is 2 $r^{4} s^{2}$

This is because we start by taking the largest factor that goes into both coefficients. Since the first coefficient is 2, we have to try 2 and 1. Since 2 is larger and goes into 36 evenly, we use that.

Then we use the smallest number of each variable. There are 4 r's in both equations. So, that is the number that we take. There are 2 s's in the first term, so we take that number.

6 0

4 years ago

In San Diego the average cost of gas is $4.15 per gallon. If a car has a fuel efficiency of 24 miles per gallon and the owner of

KIM [24]

Answer:

$25.94

Step-by-step explanation:

150 ÷ 24 = 6.25

6.25 × 4.15 = 25.9375

25.94

3 0

3 years ago

Which is the opposite side to the reference angle C?*

geniusboy [140]

Answer:

Side AB

Explanation:

The opposite side is the side that is not touching the reference angle.

3 0

3 years ago

Find the second partial derivatives of the following functions

artcher [175]

(a) z = 3x ² - 4xy + 15y ²

has first-order partial derivatives

∂z/∂x = 6x - 4y

∂z/∂y = -4x + 30y

and thus second-order partial derivatives

∂²z/∂x ² = 6

∂²z/∂x∂y = -4

∂²z/∂y∂x = -4

∂²z/∂y ² = 30

where ∂²z/∂x∂y = ∂/∂x [∂z/∂y] and ∂²z/∂y∂x = ∂/∂y [∂z/∂x].

(b) z = 4x eʸ

∂z/∂x = 4eʸ

∂z/∂y = 4x eʸ

∂²z/∂x ² = 0

∂²z/∂x∂y = 4eʸ

∂²z/∂y∂x = 4eʸ

∂²z/∂y ² = 4x eʸ

∂z/∂x = 6 ln(y)

∂z/∂y = 6x/y

∂²z/∂x ² = 0

∂²z/∂x∂y = 6/y

∂²z/∂y∂x = 6/y

∂²z/∂y ² = -6x/y ²

6 0

3 years ago