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2 years ago

Please help its urgent

Mathematics

1 answer:

ankoles [38]2 years ago

3 0

450/30

15/3x =5

x= 5

5+2y= 315

5-5+2y =315-5

2y = 310

2y/2 = 310/2

y=155

Step-by-step explanation:

450/45

2x+4y=450

2×5=10

10+(4×155)

=620/155

10/5=2

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3 years ago

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torisob [31]

I got

$- \frac{6 3}{65}$

What we know

cos a=-3/5.

sin b=12/13

Angle A interval are between 180 and 270 or third quadrant

Angle B quadrant is between 90 and 180 or second quadrant.

What we need to find

Cos(b)

Cos(a)

What we are going to apply

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Basics Sine and Cosines Identies.

1. Let write out the cos(a-b) formula.

$\cos(a - b) = \cos(a) \cos(b) + \sin(a) \sin(b)$

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