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kvv77 [185]
2 years ago
5

Please help its urgent

Mathematics
1 answer:
ankoles [38]2 years ago
3 0

450/30

15

15/3x =5

x= 5

5+2y= 315

5-5+2y =315-5

2y = 310

2y/2 = 310/2

y=155

Step-by-step explanation:

450/45

10

2x+4y=450

2×5=10

10+(4×155)

=620/155

=4

10/5=2

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Given that f(x) = x2 + 12x + 35 and g(x) = x + 7, find (f:g)(x) and express
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Answer:

2

Step-by-step explanation:

4 0
3 years ago
Consider the spreading of a rumor through a company of 1000 employees, allworking in the same building.We assume that the spread
natima [27]

Answer:

On the 12th day, the rumor would have has to all the 1000 employees

Step-by-step explanation:

Given the data in the question;

so, lets consider the rumor spreading thorough the company of 1000 employee;

the given model is; r_{n+1} = r_{n} + 1000kr_{n} ( 1000 - r_{n} )

where k is the parameter that depends on how fast the rumor spreads, n is the number of days.

now, lets assume k = 0.0001, lets also assume r₀ = 4

so to find how soon all 1000 employees  will have heard the rumor  ;

let n be;

then r1 will be;

r1 = r₀ + ( 0.001)r₀(1000-r₀ )

so

r1 = 4 + ( 0.001) × 4× (1000 - 4 )

r1 = 7.984

r2 will be;

r2 = r1 + ( 0.001)r1(1000-r1 )

r2 =  7.984 + ( 0.001) × 7.984 × (1000 - 7.984 )

r2 = 15.904255744

   

r3  will be;

r3 = r2 + ( 0.001)r2(1000-r2 )  

r3 = 15.904255744 + ( 0.001) × 15.904255744 × (1000 - 15.904255744 )

r3 = 31.555566137

Using the same formula and procedure by substituting n = 1,2,3,4,5,6,7,8,9,10,11,12.

we will have;

n        rₙ

0        4

1        7.984

2       15.904255744

3       31.555566137

4       62.1153785

5       120.372437

6       226.25535

7       401.319217

8       641.58132

9       871.53605

10     983.497013

11      999.727651

12     999.999926

Therefore, On the 12th day, the rumor would have has to all the 1000 employees

 

5 0
3 years ago
The amount of time a passenger waits at an airport check-in counter is random variable with mean 10 minutes and standard deviati
Stolb23 [73]

Answer:

(a) less than 10 minutes

= 0.5

(b) between 5 and 10 minutes

= 0.5

Step-by-step explanation:

We solve the above question using z score formula. We given a random number of samples, z score formula :

z-score is z = (x-μ)/ Standard error where

x is the raw score

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Standard error : σ/√n

σ is the population standard deviation

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x = 10 μ = 10, σ = 2 n = 50

z = 10 - 10/2/√50

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P(x<5) = 0

Using the z table to find the probability

P(z ≤ 0) = P(z = -17.67767) = P(x = 5)

= 0

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z = 10 - 10/2/√50

z = 0 / 0.2828427125

z = 0

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= 0.5 - 0

= 0.5

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