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3 years ago

HELP WILLMARK BRAINLIEST.!!!!

Mathematics

1 answer:

navik [9.2K]3 years ago

6 0

The answer is A i'm positive I used my caculater

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Is 25,365 cm greater or less than 30 m

anyanavicka [17]

25365cm÷100=m
=253.65m
25365 is less than 30m

6 0

3 years ago

(Click the picture to see math question) please help I’ll mark brainliest

FromTheMoon [43]

Answer:

g(x) = f(x + 2)

Step-by-step explanation:

The x value has been translated by 2

<em>Feel free to mark it as brainliest :D</em>

3 0

3 years ago

Lee associates borrowed $60,000. The company plans to set up a sinking fund that will pay back the loan at the end of 12 years.

erma4kov [3.2K]

If your choices are the following:
A.<span> $1,350
B. $1,536
</span>C.<span> $1,653
</span>D.<span> $5,163
</span>E.<span> None of these
</span>
Then the answer is B. $1,536.

Solution:
<span>$60,000 x .0256
</span>=<span>1,536</span>

7 0

3 years ago

Perform the indicated operation. Be sure the answer is reduced.

avanturin [10]

<h3>Given Equation:-</h3>

$\boxed{ \rm \frac{4x^{2}y^{3}z}{9} \times \frac{45y}{8 {x}^{5} {z}^{5} }}$

<h3>Step by step expansion:</h3>

$\dashrightarrow \sf\dfrac{4x^{2}y^{3}z}{9} \times \dfrac{45y}{8 {x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{ \cancel4x^{2}y^{3}z}{9} \times \dfrac{45y}{ \cancel8 {x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{9} \times \dfrac{45y}{2{x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{ \cancel9} \times \dfrac{ \cancel{45}y}{2{x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{1} \times \dfrac{5y}{2{x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{0}y^{3}z}{1} \times \dfrac{5y}{2{x}^{5 - 2} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{y^{3}z}{1} \times \dfrac{5y}{2{x}^{3} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{y^{3}z {}^{0} }{1} \times \dfrac{5y}{2{x}^{3} {z}^{3 - 1} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{y^{3}}{1} \times \dfrac{5y}{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \sf \dfrac{5y \times {y}^{3} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \sf \dfrac{5y {}^{0} \times {y}^{3 + 1} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \sf \dfrac{5 \times {y}^{4} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \bf \dfrac{5 {y}^{4} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\therefore \underline{ \textbf{ \textsf{option \red c \: is \: correct}}}$

8 0

2 years ago

Can someone help me with this math problem ?? Pls it’s for my final !

Airida [17]

Answer:

221.87 feet

Step-by-step explanation:

Given that,

A 525 ft cable runs from the top of an antenna to the ground.

The angle of elevation made by the ground to the top of an antena 25°

We need to find the height of the antenna.

Using trigonometry,

Hypotenuse, H = 525 ft

θ = 25°

So,

$\sin\theta=\dfrac{P}{H}\\\\P=H\sin\theta\\\\P=525\times \sin(25)\\\\P=221.87\ ft$

So, the height of the antenna is equal to 221.87 feet.

4 0

3 years ago