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Arte-miy333 [17]
3 years ago
13

The steps below describe the construction of a line AG which is parallel to segment PQ and passes through a point A outside of P

Q:
Which statement describes the next step? (5 points)
The width of the compass is adjusted to De, and an arc is drawn from Point E.
The width of the compass is adjusted to DE, and an arc is drawn from Point A.
The width of the compass is adjusted to DE, and an arc is drawn from Point F.
The width of the compass is adjusted to DE, and an arc is drawn from Point D.
Mathematics
2 answers:
Wittaler [7]3 years ago
4 0

Answer:

“The width of the compass is adjusted to DE, and an arc is drawn from point F.”

Vesna [10]3 years ago
3 0

Answer:

C

Step-by-step explanation:

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Suppose you have a water-balloon launcher. The balloon is 3 ft high when it leaves the launcher. Use the equation 0 = ?16t2 + 38
mario62 [17]

Answer:

t = 2.5 s

Step-by-step explanation:

Suppose you have a water-balloon launcher. The balloon is 3 ft high when it leaves the launcher. Its equation is :

16t^2 + 38.8t + 3 =0

The above equation is a quadratic equation. The general equation is :

ax^2+bx+c=0

Here, a = 16, b = 38.8 and c = 3

The solution of quadratic equation is given by :

x=\dfrac{-b\pm \sqrt{b^2-4ac} }{2a}\\\\t=\dfrac{-38.8\pm \sqrt{(38.8)^2-4\times (-16)\times 3} }{2\times (-16)}\\\\t=\dfrac{-38.8+\sqrt{(38.8)^{2}-4\times-16\times3}}{-2\times16}, \dfrac{-38.8-\sqrt{(38.8)^{2}-4\times-16\times3}}{-2\times16}\\\\t=-0.075\ s,2.5\ s

So, at t = 2.5 s the balloon is in air.

8 0
3 years ago
Find the slope of the line please help!
Jlenok [28]
Slope = rise/run
Rise = 3, run = 8
Downwards line = negative
Slope = -3/8
3 0
3 years ago
In right triangle ABC, A = 15°, C=37, and ZC is the right angle. Solve the triangle. Round to the nearest tenth, if necessary.
Ilya [14]

Answer:

well to get that you add all them and divide

Step-by-step explanation:

8 0
3 years ago
What is the absolute value of 56
Karo-lina-s [1.5K]
56 because it is the distance of a number from zero! Hope that helped!
3 0
3 years ago
Read 2 more answers
Write an equation in standard form of an ellipse that is 28 units high and 20 units wide
cestrela7 [59]
The standard form of ellipse with vertical major axis and center at the origin is:
x^2/b^2+y^2/a^2=1, a>b
2a=length of the major axis=28
a=14
a^2=196

2b=length of minor axis=20
b=10
b^2=100

x^2/196+y^2/100=1

making y the subject we get

y=5/7(196-x²)^0.5
8 0
3 years ago
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