The steps below describe the construction of a line AG which is parallel to segment PQ and passes through a point A outside of P
2 answers:
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Answer:
Step-by-step explanation:
The table shows a set of x and y values, thus showing a set of points we can use to find the equation.
1) First, find the slope by using two points and substituting their x and y values into the slope formula, . I chose (-3, 13) and (0,17), but any two points from the table will work. Use them for the formula like so:
Thus, the slope is .
2) Next, identify the y-intercept. The y-intercept is where the line hits the y-axis. All points on the y-axis have a x value of 0. Thus, (0,17) must be the y-intercept of the line.
3) Finally, write an equation in slope-intercept form, or format. Substitute the
and
for real values.
The represents the slope of the equation, so substitute it for
. The
represents the y-value of the y-intercept, so substitute it for 17. This will give the following answer and equation: