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inessss [21]
3 years ago
7

Write a program that accepts a phrase of unspecified length on the command line. For example: prompt% letter print Operating Sys

tems Class at Kent-State The main0 in this program has to create two threads running functions (vow and cons). The threads should take turns printing the respective words of the phrase supplied on the command line. The vow thread should print all the words that start with a vowel and the cons thread should print all words starting with a consonant. Note that the main thread (running main0) should not print anything itself-the output should be supplied by the threads that it creates. The order of words in the phrase should not be changed in the printout. Your program should work for any phrase of any reasonable length, not just the one given in the example. The output of your program should looks similar to the following prompt% letter print Operating Systems Class at Kent-State vow: Operating cons: Systems cons: Class vow: at cons: Kent-State In this part you are not allowed to use synchronization primitives such as mutexes for thread coordination. You can use sched yield0 to relinquish control of the CPU

Computers and Technology
1 answer:
Sedaia [141]3 years ago
3 0

Answer:

Check the explanation

Explanation:

#define _MULTI_THREADED

#include <pthread.h>

#include <stdio.h>

#include <errno.h>

#define           THREADS          2

int               i=1,j,k,l;

int argcG;

char *argvG[1000];

void *threadfunc(void *parm)

{

int *num;

num=(int*)parm;

while(1)

   {

   if(i>=argcG)

   break;

   if(*num ==1)

   if(argvG[i][0]=='a' ||argvG[i][0]=='2'||argvG[i][0]=='i' ||argvG[i][0]=='o' ||argvG[i][0]=='u')

   {

   printf("%s\n",argvG[i]);

   i++;

   continue;

   }

    if(*num ==2)

   if(!(argvG[i][0]=='a' ||argvG[i][0]=='2'||argvG[i][0]=='i' ||argvG[i][0]=='o' ||argvG[i][0]=='u'))

   {

   printf("%s\n",argvG[i]);

   i++;

   continue;

   }

   sched_yield();

   }

return NULL;

}

int main(int argc, char *argv[])

{

pthread_t            threadid[THREADS];

int                  rc=0;

int                  loop=0;

int arr[2]={1,2};

argcG=argc;

for(rc=0;rc<argc;rc++)

argvG[rc]=argv[rc];

printf("Creating %d threads\n", THREADS);

for (loop=0; loop<THREADS; ++loop) {

     rc =pthread_create(&threadid[loop], NULL, threadfunc,&arr[loop]);

}

for (loop=0; loop<THREADS; ++loop) {

   rc = pthread_join(threadid[loop], NULL);

}

printf("Main completed\n");

return 0;

}

The below attached image is a sample output

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Explanation:

Sorry if I am wrong

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Create a text file content.txt and copy-paste following text (taken from Wikipedia) into it: A single-tasking system can only ru
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8 0
3 years ago
Write a Python 3 script in PyCharm that will simulate the game of "Rock, Paper, Scissors": Display a header and the simple rules
mr Goodwill [35]

Answer:

'''

Rock, Paper, Scissors:

The Rules:

If player1's move equivalent to player2's move, "It's a tie".

"rock" beats "scissors", "scissors" beats "paper", and "paper" beats "rock"

'''

player_1 = input("Player 1's move: ")

print('*** NO CHEATING ***' * 20)

player_2 = input("Player 2's move: ")

if player_1 or player_2 not in ["rock", "paper", "scissors"]:

 print("Invalid input!")

if player_1 == player_2:

   print("It's a tie")

else:

   if player_1 == "rock":

       if player_2 == "scissors":

           print("Player 1 won")

       elif player_2 == "paper":

           print("Player 2 won")

   elif player_1 == "scissors":

       if player_2 == "paper":

           print("Player 1 won")

       elif player_2 == "rock":

           print("Player 2 won")

   elif player_1 == "paper":

       if player_2 == "rock":

           print("Player 1 won")

       elif player_2 == "scissors":

           print("Player 2 won")

Explanation:

In the comment part, put the header and the rules of the game

Ask the user to enter the player1's move

Print the asterisks

Ask the user to enter the player2's move

If any of the input is not "rock", "paper", "scissors", state that the input is invalid

Check the inputs. If they are equal, print that it is a tie. Otherwise:

If player1's move is rock. Check player2's move. If it is "scissors", player1 wins. If it is "paper", player2 wins

If player1's move is scissors. Check player2's move. If it is "paper", player1 wins. If it is "rock", player2 wins

If player1's move is paper. Check player2's move. If it is "rock", player1 wins. If it is "scissors", player2 wins

7 0
3 years ago
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