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Lisa [10]
3 years ago
13

The cylinders are similar the volume of the larger cylinder is 1600 cubic centimeters what is the volume of the smaller cylinder

Mathematics
1 answer:
cestrela7 [59]3 years ago
8 0

We are given Volume of the larger cylinder is = 1600 cubic centimeters.

Height of the larger cylinder = 16 cm.

We know formula of volume of a cylinder V=\pi r^2h, where r is the radius of cylinder,  h is the height of the cylinder.

Plugging value of V and h of larger cylinder, we get

1600=\pi r^2(16).

Dividing both sides by 16, we get

\frac{1600}{16}=\frac{\pi r^2 (16)}{16}

r^2=100

Taking square root on both sides, we get

r=10.

Therefore, radius of the larger cylinder is 10 cm.

We are given cylinders are similar .

<u>Note: The radii and heights of similiar cylinders are in same ratio.</u>

Therefore, we can setup a proportion:

Let us take radius of small cylinder is x.

\frac{x}{10}=\frac{4}{16}

\frac{x}{10}=\frac{1}{4}

Multiplying both sides by 10, we get

10 \times \frac{x}{10}=10 \times\frac{1}{4}

x=2.50.

Therefore, radius of the small cylinder = 2.5 cm.

Now, plugging radius =2.5 and height  = 4 in the formula of volume the cylinder, we get

V=\pi (2.5)^2(4)=\pi (6.25)(4) =25 \pi \ cm^3.

Therefore, correct option is 25 pi cm^3.

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Answer:

The calculated value     t =   2.366 > 2.0301 at 0.05 level of significance

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Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that the first sample size 'n₁' = 22

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<u><em>Alternative Hypothesis:H₁:</em></u>

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         T-test statistic

               t = \frac{x^{-} _{1} -x^{-} _{2} }{\sqrt{S^{2} (\frac{1}{n_{1} }+\frac{1}{n_{2} } ) } }

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The calculated value     t =   2.366 > 2.0301 at 0.05 level of significance

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