1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nataly [62]
3 years ago
6

Put this equation in standard form Y+5=-(x+3)?

Mathematics
1 answer:
lisabon 2012 [21]3 years ago
4 0

Answer: y = x - 2

Step-by-step explanation:

Subtract 5 from both sides.

You might be interested in
Simplify this problem
ikadub [295]

Answer:

\boxed{  \frac{ \sqrt[3]{ {x}^{11} } }{4} }

Step-by-step explanation:

=  >  \frac{ {x}^{4} }{ \sqrt[3]{64x} }  \\  \\  =  >  \frac{ {x}^{4} }{ {(64x)}^{ \frac{1}{3} } }  \\  \\  =  >  \frac{ {x}^{4} }{ ({64}^{ \frac{1}{3} }  )\times  ({x}^{ \frac{1}{3} } )}  \\  \\  =  >  \frac{ {x}^{4} }{ ({( {4}^{3} )}^{ \frac{1}{3} }) \times(  {x}^{ \frac{1}{3} }  )}  \\  \\  =  >   \frac{ {x}^{4} }{ ({4}^{ \cancel{3} \times  \frac{1}{ \cancel{3}} } ) \times(  {x}^{ \frac{1}{3} }  )}   \\  \\  =  >  \frac{ {x}^{4} }{4 {x}^{ \frac{1}{3} } }  \\  \\  =  >  \frac{ {x}^{4 -  \frac{1}{3} } }{4}  \\  \\  =  >  \frac{ {x}^{ \frac{12 - 1}{3} } }{4}  \\  \\  =  >  \frac{ {x}^{ \frac{11}{3} } }{4}  \\  \\  =  >   \frac{ \sqrt[3]{ {x}^{11} } }{4}

7 0
3 years ago
divide a x cubed space plus 3 x squared space minus b x minus 6 space b y space x to the power of 2 space end exponent plus 3 x
marta [7]

Answer:

ax^3+3x^2-bx-6/x^2+3x+2 ( Please specify the equation if I'm wrong)

Step-by-step explanation:

ax^3+3x^2-x^2-bx-3x-6-2

=ax^3+2x^2-x(b+3)-8

3 0
3 years ago
Sam has 1,300 dimes. Anna has 1/10 the number of dimes Sam has. How many dimes does Anna have?
Nata [24]
1,300÷10=130
Anna has 130 dimes
7 0
3 years ago
Points X and are endpoints of a diameter of OW. Point Z is Points X and are endpoints of (Tother point on the circle. Find the p
eimsori [14]

<u>Corrected Question</u>

Points X and Y are endpoints of a diameter of Circle W. Point Z is another  point on the circle. Find the probability that \angle XZY is a right angle.

Answer:

Probability=1

Step-by-step explanation:

<u>Theorem</u>

  • If an Inscribed angle intercepts a semicircle, the angle is a right angle.

Given that X and Y are endpoints of a diameter of Circle W and point Z is on the circle's circumference.

I have prepared a diagram which is attached.

Then,  \angle XZY is an angle which intercepts a semicircle.

By the theorem above,  \angle XZY is a right angle.

Therefore, the probability that \angle XZY is a right angle =1

5 0
3 years ago
PLS HELP SUPER EASY WILL GIVE BRAINLIEST
anzhelika [568]

Answer:

-2x +4 = 20

Step-by-step explanation:

given

- 2x + 4 = 20

by making x the subject, you need to subtract 4 from 20

thus

- 2x = 20 - 4

- 2x = 16

and also you need to divide through by -2

\frac{ - 2x}{2}  =  \frac{16}{ - 2}

x =  - 8

3 0
3 years ago
Read 2 more answers
Other questions:
  • Tracy stopped at the convenience store on her way to school. With tax, bottles of soda cost 1.50 and bags of chips cost 2.50. If
    5·1 answer
  • What is the period of a wave if the wavelength is 100 m and the speed is 200 m/s?
    5·2 answers
  • Two teams of interns are wrapping donated gifts at a hospital. if the teams work alone, team a can wrap all of the gifts in 7 ho
    8·1 answer
  • The polynomial 6x2 + 37x – 60 represents an integer. Which expressions represent integer factors of 6x2 + 37x – 60 for all value
    6·2 answers
  • What is 2+4/5x15-190?
    13·2 answers
  • Ratios that are equivalent to 7/6
    14·2 answers
  • Determine f’s end behavior <br><br> f(x)= -5x^6+8x^5-1/ x^2 -9
    7·1 answer
  • Why are these triangles similar?​
    6·1 answer
  • What's (2x) ^3 in expanded notation form?
    9·2 answers
  • I need Help! ASAP: The current temperature in Lansdowne is 20°F. This is 6 degrees less than twice the temperature that it was f
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!