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daser333 [38]
3 years ago
7

Two cars leave towns 360 kilometers apart at the same time and travel toward each other. One car's rate is 12 kilometers per hou

r less than the other's. If they meet in 2 hours, what is the rate of the slower car?
Mathematics
1 answer:
mixer [17]3 years ago
5 0
Let x = speed of the first car

the second car is 12 km slower so the seconds car speed is x-12

 they each drove 2 hours so 1st car = 2x
2nd car = 2(x-12)
 
they drove 360 km
 so you have 2x + 2(x-12) = 360
 solve for x

2x+2(x-12) = 360

2x + 2x-24 = 360

4x-24 = 360

4x = 384
x = 384/4
x = 96

1st car drove at 96 km per hour

slower car drove at 96-12 = 84 km per hour



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