Answer:
1.35
Step-by-step explanation:
I believe this is right but it could be wrong. Hope this helps! <3
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The answer is: <u>2(k2−4k)(2c+5)</u>
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Step:
* Consider 2ck2+5k2−8ck−20k. Do the grouping 2ck2+5k2−8ck−20k=(2ck2+5k2) +(−8ck−20k), and factor out k2 in the first and −4k in the second group.
* Factor out the common term 2c+5 by using the distributive property.
* Rewrite the complete factored expression.
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Answer:
x=3 & y=162
Step-by-step explanation:
it may help you
X ^2 +6x+ 5
(x+2)(x+3)
2 + 3 = 5
While also 2•3= 6
The two numbers have to equal b when multiplied and c when added
