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2 years ago

14

Xander says that it is not possible to draw a quadrilateral that is not a parallelogram and not a trapezoid. Devin says it is po

ssible. Explain who is correct.

1 answer:

Alik [6]2 years ago

4 0

Devin is correct because you can draw parallelograms that aren't trapezoid, such as rectangles or squares

I hope I've helped!

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fenix001 [56]

Move all the logarithms on the left hand side, and all the constants on the other:

$\log_2(x-2) - \log_2(x) = -1$

Use the rule of logarithms

$\log_a(b) - \log_a(c) = \log_a\left(\dfrac{b}{c}\right)$

To rewrite the equation as

$\log_2\left(\dfrac{x-2}{x}\right) = -1$

Evaluate 2 to the power of each side:

$\dfrac{x-2}{x} = 2^{-1} = \dfrac{1}{2}$

Multiply both sides by 2x:

$2(x-2) = x \iff 2x-4 = x \iff x = 4$

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X2 + 5x - 14 Select one of the factors of the quadratic expression.

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The equation factored would be (x+7)(x-2). As 7-2=5 and (7)(2)=14.

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Which pair of undefined terms is used to define a ray?

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The answer to this problem is line segment

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