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drek231 [11]
4 years ago
15

An experiment involves 17 participants. From these, a group of 3 participants is to be tested under a special condition. How man

y groups of 3 participants can
be chosen, assuming that the order in which the participants are chosen is irrelevant?
​
Mathematics
1 answer:
lakkis [162]4 years ago
8 0

Answer: 680

Step-by-step explanation:

When order doesn't matter,then the number of combinations of choosing r things out of n = ^nC_r=\dfrac{n!}{r!(n-r)!}

Given: Total participants = 17

From these, a group of 3 participants is to be tested under a special condition.

Number of groups of 3 participants chosen = ^{17}C_3=\dfrac{17!}{3!(17-3)!}\

^{17}C_3=\dfrac{17!}{3!(17-3)!}\\\\=\dfrac{17\times16\times15\times14!}{3\times2\times14!}\\\\=680

Hence, there are 680 groups of 3 participants can  be chosen,.

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