Question

Christina rolls a number cube twice.What is the probability she rolls a prime number and then an odd number?

Answer 1

The probability is 3/6 (1/2) as there are 3 prime numbers on a dice (2,3,5) and also 3 odd numbers on a dice (1,3,5)

Answer 2

Christina rolls a number cube twice.

Number of outcomes in a cube = 1,2,3,4,5,6 = 6 outcomes

Prime numbers = 2,3,5 = 3 outcomes

Odd numbers = 1,3,5 = 3 outcomes

probability that she rolls a prime number = $\frac{outcome of a prime number }{total number of outcomes}$ =$\frac{3}{6} = \frac{1}{2}$

probability that she rolls a odd number = $\frac{outcome of a odd number }{total number of outcomes}$ =$\frac{3}{6} = \frac{1}{2}$

probability (a prime number and then an odd number) =

$\frac{1}{2}$ * $\frac{1}{2}$ = $\frac{1}{4}$