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3 years ago

Christina rolls a number cube twice.What is the probability she rolls a prime number and then an odd number?

Mathematics

2 answers:

Arisa [49]3 years ago

5 0

The probability is 3/6 (1/2) as there are 3 prime numbers on a dice (2,3,5) and also 3 odd numbers on a dice (1,3,5)

ella [17]3 years ago

3 0

Christina rolls a number cube twice.

Number of outcomes in a cube = 1,2,3,4,5,6 = 6 outcomes

Prime numbers = 2,3,5 = 3 outcomes

Odd numbers = 1,3,5 = 3 outcomes

probability that she rolls a prime number = $\frac{outcome of a prime number }{total number of outcomes}$ = $\frac{3}{6} = \frac{1}{2}$

probability that she rolls a odd number = $\frac{outcome of a odd number }{total number of outcomes}$ = $\frac{3}{6} = \frac{1}{2}$

probability (a prime number and then an odd number) =

$\frac{1}{2}$ * $\frac{1}{2}$ = $\frac{1}{4}$

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A theater has 1200 seats. each row has 20 seats. write and solve an equation to find the number xx of rows in the theater. an eq

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3 years ago

What is 7/8 minus 1/4?

erastovalidia [21]

7/8 -1/4
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3 years ago

When the members of a family discussed where their annual reunion should take place, they found that out of all the family mem

Doss [256]

Answer:

The total number of family members is 21.

Step-by-step explanation:

To solve this problem, we must build the Venn's Diagram of these sets.

I am going to say that:

-The set A represents those that would not go to a park.

-The set B represents those who would not go to a beach.

-The set C represents those who would not go to the family cottage.

The value d represents those who would go to all three places.

We have that:

$A = a + (A \cap B) + (A \cap C) + (A \cap B \cap C)$

In which a are those that would only not go to a park, $A \cap B$ are those who would not got to a park or to the beach, $A \cap C$ are those who would not go to a park or to the famili cottage. And $A \cap B \cap C$ are those that would not go to any of these places.

By the same logic, we have:

$B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)$

$C = c + (A \cap C) + (B \cap C) + (A \cap B \cap C)$

This diagram has the following values:

$a,b,c,d,(A \cap B), (A \cap C), (B \cap C), (A \cap B \cap C)$

The total number of family members is the sum of all these values:

$T = a + b + c + d + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C)$

We start finding the values from the intersection of the three sets

5 would not go to a park or a beach or to the family cottage.

This means that $A \cap B \cap C = 5$

1 would go to all three places. This means that $d = 1$ .

8 would go to neither a park nor the family cottage

This means that:

$A \cap C + (A \cap B \cap C) = 8$

$A \cap C = 3$

8 would go to neither a beach nor the family cottage

$B \cap C + (A \cap B \cap C) = 8$

$B \cap C = 3$

7 would go to neither a park nor a beach

$A \cap B + (A \cap B \cap C) = 7$

$A \cap B = 2$

15 would not go to the family cottage

$C = 15$

$C = c + (A \cap C) + (B \cap C) + (A \cap B \cap C)$

$15 = c + 3 + 3 + 5$

$c = 4$

12 would not go to a beach

$B = 12$

$B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)$

$12 = b + 3 + 2 + 5$

$b = 2$

11 would not go to a park

$A = 11$

$A = a + (A \cap B) + (A \cap C) + (A \cap B \cap C)$

$11 = a + 2 + 3 + 5$

$a = 1$

Now, we can find the total number of family members.

$T = a + b + c + d + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C)$

$T = 1 + 2 + 4 + 1 + 2 + 3 + 3 + 5$

$T = 21$

The total number of family members is 21.

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3 years ago

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Nataly_w [17]

This is your perfect answer

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2 years ago

What effect does replacing x with x + 2 have on the graph for the function f(x) ?

IrinaK [193]

The answer is A.

When replacing the variable 'x' by 'x + 2' the graph is shifted 2 units to the left. When we replace the variable, the function changes

from
$f(x) = |x - 3| + 2$

To
$f(x) = |(x + 2) - 3| + 2$
$f(x) = |x - 1| + 2$

And therefore the function is shifted 2 to the left.

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3 years ago