The width of a rectangle is 5 feet less than the length. The perimeter is 62. Find the length and width of the rectangle.
2 answers:
Answer:
see below and attached.
Step-by-step explanation:
Perimeter (P) = 2 L (Length) + 2 W (Width)
where P = 62
W = L - 5
P = 2L + 2W
62 = 2L + 2(L -5)
62 = 2L + 2L - 10
72 = 4L
L = 72/4
L = 18
W = L - 5
W = 18 - 5
W = 15
Variables : P, L, W
Model equation: P = 2L + 2W
Length of the rectangle: 18
Width of the rectangle: 13
Perimeter formula: p = 2(w + l)
The perimeter is 62.
p = 62
The width of a rectangle is 5 feet less than the length.
w = l - 5
Substitute and solve.
62 = 2[(l - 5) + l)]
62 = 2l + 2l - 10
62 = 4l - 10
72 = 4l
18 = l
Substitute and solve for the width
w = 18 - 5
w = 13
Therefore, the length is 18 and the width is 13.
Best of Luck!
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