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2 years ago

An angle is a right angle if and only if it measures 90°

Mathematics

2 answers:

dmitriy555 [2]2 years ago

5 0

Answer:

A right angle measures 90°

Step-by-step explanation:

rewona [7]2 years ago

3 0

If an angle is a right angle, then it measures 90 degrees

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Help 10 minutes!!!!!!!

butalik [34]

This ordered pair makes both statements true, so A, B, and D are all the correct answers!

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3 years ago

Find the trig ratio. Reduce to<br> lowest terms.

Vlad [161]

COS A=0.8

Step-by-step explanation:

2^6+8^2

100

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2 years ago

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If you are selling bag of candy would you want ti sell the candy in ounces or pounds? Explain.

7nadin3 [17]

You would want to sell the bag of candy in ounces, unless you have way too much candy.

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3 years ago

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Simplify by expressing fractional exponents instead of radicals

igomit [66]

Answer:

$a^{\frac{1}{2}}b^{\frac{1}{2}}$

Step-by-step explanation:

Given:

The expression in radical form is given as:

$\sqrt{ab}$

We need to express this in fractional exponent form.

We know that,

$\sqrt a=a^{\frac{1}{2}}$

Also, $\sqrt{ab}=\sqrt a\times \sqrt b$

Now, clubbing both the properties of square root function, we can rewrite the given expression as:

$\sqrt{ab}=\sqrt a \times \sqrt b\\\\\sqrt{ab}=a^{\frac{1}{2}}\times b^{\frac{1}{2}}\\\\\therefore \sqrt{ab}=a^{\frac{1}{2}}b^{\frac{1}{2}}$

So, the given expression in fractional exponents form is $a^{\frac{1}{2}}b^{\frac{1}{2}}$ .

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3 years ago

How does the sample size affect the validity of an empirical argument? A. The larger the sample size the better. B. The smaller

astra-53 [7]

Answer:

A. The larger the sample size the better.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{\frac{p(1-p)}{n}}$

In this question:

We have to look at the standard error, which is:

$s = \frac{\sigma}{\sqrt{n}}$

This means that an increase in the sample size reduces the standard error, and thus, the larger the sample size the better, and the correct answer is given by option a.

7 0

3 years ago