Answer:
2 15/26
Step-by-step explanation:
Make them both fractions and find a common demoninator. 8 1/13 = 105/13 and 5 1/2 = 11/2. A common denominator is 26, so 105/13 * 2 = 210/26 and 11/2 * 13 = 143/26. You then subtract the fractions to find out how much is left to walk, 210-143 = 67/26, or 2 15/26.
Answer:
SOHCAHTOA.
Step-by-step explanation:
acronym is an abbreviation formed from the initial letters of other words and pronounced as a word
The acronym for sin cosine and tangent is
SOHCAHTOA
Sine =Opposite over Hypotenuse
Cosine= Adjacent over Hypotenuse
Tangent= Opposite over Adjacent
Answer:
Step-by-step explanation:
it means that
125-30 < u < 125+30 so
95 < u < 155
it gives
Answer:
It's C
Step-by-step explanation:
Simplify the expression
The average velocity of the particle in the time interval between 3s and 5s is 20 ms⁻¹ and its instantaneous velocity at 4s is 20 ms⁻¹.
How to determine average velocity and instantaneous velocity?
Average velocity is defined as the body's overall displacement divided by its time of motion. While instantaneous velocity is defined as a body's speed at a certain instant in time, or its displacement at that instant. When the velocity is constant, average and instantaneous velocities will equalize at just one condition.
The definition of instantaneous velocity is the rate of change of position over a relatively brief time period (almost zero). Simply said, the speed of an object at that precise moment. The definition of instantaneous velocity is "The velocity of an item in motion at a certain point in time." The instantaneous velocity of an object may be equal to its standard velocity if it has uniform velocity.
Mathematically, average velocity = [s(t₂) - s(t₁)]/[t₂ - t₁]
Instantaneous velocity at time, t is = (ds/dt) at time = t
Given, the displacement for the particle is given by s = 3t² - 4t + 5
Time interval, t₁ = 5s and t₂ = 3s;
Using formula in literature, average velocity of the particle in the time interval between 3s and 5s is:
Average velocity = (s(5) - s(3))/(5 - 3) = (60 - 20)/2 = 20 ms⁻¹
Instantaneous velocity at t = 4 is ds/dt at that time-frame:
Now, v = ds/dt = 6t -4
Now, v(4) = 6(4) - 4 = 20 ms⁻¹
The average velocity of the particle in the time interval between 3s and 5s is 20 ms⁻¹ and its instantaneous velocity at 4s is 20 ms⁻¹.
To learn more about this, tap on the link below:
brainly.com/question/2234298
#SPJ9