Answer:
La arista de la bodega debe medir 6 metros.
Step-by-step explanation:
Podemos encontrar la arista de la bodega sabiendo su volumen:
En donde:
V: es el volumen de un cubo = 216 m³
a: es la arista del cubo =?
La arista del cubo es:
![a = \sqrt[3]{V} = \sqrt[3]{216 m^{3}} = 6 m](https://tex.z-dn.net/?f=%20a%20%3D%20%5Csqrt%5B3%5D%7BV%7D%20%3D%20%5Csqrt%5B3%5D%7B216%20m%5E%7B3%7D%7D%20%3D%206%20m%20)
Por lo tanto, la arista de la bodega debe medir 6 metros.
Espero que te sea de utilidad!
The area needed is at least 170.5 ft².
Let w = the width of the rectangular area.
Because the length is 15.5 ft, therefore the calculated area should be at least 170.5 ft². That is
(15.5 ft)*(w ft) ≥ 170.5 ft²
w ≥ 170.5/15.5
w ≥ 11 ft
Answer: w ≥ 11 ft
Answer:
True
Step-by-step explanation:
An input is always anything that equals a sum.
Input: Small-Medium-Large
Output: Prices
I am going to assume ‘centimetre’ was a typo.
A^2 + B^2 = C^2
C^2 - A^2 = B^2
32 = B^2
Square root both sides
B = 5.7m high
The ladder will reach 5.7 meters high
The form of the linne is given by
Y=mx +b
Where b is the y intercept of the line
That is the point where the line cuts the y axis
So here b= -3
So
Equation is
Y=1/3 x +(-3)
Answer in place of question mark is -3
