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Helen [10]
3 years ago
14

What is the common factor of this term 25a^3b^2=(5a^2b^2) (?)

Mathematics
1 answer:
solmaris [256]3 years ago
8 0
25a^3b^2=5\cdot5\cdot a^{2+1}b^2=(5a^2b^2)(5a)
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A+9 write this in a verbal expression
balandron [24]

Nine more than a variable "a".

7 0
3 years ago
A triangle in the coordinate plane has vertices ????(0,10), ????(−8,8), and ????(−3,5). Is it a right triangle? If so, at which
GaryK [48]

Answer:

It is a right triangle, the right angle is at the point (-3, 5)

Step-by-step explanation:

The first step is to locate the points of the vertices in a plane, in this case they are (0.10), (-8.8) and (-3.5). The desmostration of this is shown in the attached image.

As we can see it is formed a right triangle (the figure outlined in red), and the rigth angle is the one at the point (-3,5).

5 0
3 years ago
Please help with this
slava [35]

Answer:

D) x=\frac{-2+-2\sqrt{7} }{3}

Step-by-step explanation:

The quadratic formula is : \frac{-b+-\sqrt{b^2-4ac} }{2a}

A in terms of this question=9

B in terms of the question is 12

C in terms of the question is -24.

This question is an example of a quadratic equation. To work this out you may first need a calculator. The first step is to substitute the values of a,b and c into the formula.  So once substituted the formula of \frac{-b+-\sqrt{b^2-4ac} }{2a} becomes \frac{(-12)+-\sqrt{(12)^2-4*(9)*(-24)} }{2(9)}. Although when written in a calculator there will not be a plus and minus button and so you would have to do this separately.

However when substituting the values it would be best practice to put them in brackets.

1) Substitute the values into the equation for +.

\frac{(-12)+\sqrt{(12)^2-4*(9)*(-24)} }{2(9)}=\frac{-2+2\sqrt{7} }{3} /1.097167541

2) Substitute the values into the equation for -.

\frac{(-12)-\sqrt{(12)^2-4*(9)*(-24)} }{2(9)}=\frac{-2+2\sqrt{7} }{3} /-2.430500874

8 0
3 years ago
What is the last one number 12
rosijanka [135]
What is the last one number 12
8 0
3 years ago
In a certain​ lottery, you must select 5 numbers​ (in any​ order) out of 26 correctly to win. a. How many ways can 5 numbers be
Step2247 [10]

Answer:

a. 7893600

b.\ \dfrac{1}{26}

Step-by-step explanation:

Given that there are 26 numbers out of which 5 numbers are to be chosen.

Here repetition is not allowed.

For each of the 5 cases, the total number of possibilities will keep on decreasing by 1.

1st case, number of possibilities = 26

2nd case, number of possibilities = 25

3rd case, number of possibilities = 24

4th case, number of possibilities = 23

5th case, number of possibilities = 22

a. Total number of possibilities = 26 \times25 \times24 \times23 \times22 = <em>7893600</em>

b. Probability of winning by choosing one number:

Formula for probability of an event E can be observed as: P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}

Number of favorable cases = 1

Total number of cases = 26

So, required probability:

P(E) = \dfrac{1}{26}

So, the answers are:

a. 7893600

b.\ \dfrac{1}{26}

5 0
3 years ago
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