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Helen [10]
3 years ago
14

What is the common factor of this term 25a^3b^2=(5a^2b^2) (?)

Mathematics
1 answer:
solmaris [256]3 years ago
8 0
25a^3b^2=5\cdot5\cdot a^{2+1}b^2=(5a^2b^2)(5a)
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Answer:

6.21 seconds

Step-by-step explanation:

The position function of a free-falling object is,

s(t) = -16t^2+v_0t+s_0

Where,

s_0 = initial height of the object,

v_0 = initial velocity of the object,

Here,

s_0=400\text{ feet}

v_0=35\text{ feet per sec}

Hence, the height of the ball after t seconds,

s(t)=-16t^2+35t+400

When s(t) = 0,

\implies -16t^2+35t+400=0

t=\frac{-35\pm \sqrt{35^2-4\times -16\times 400}}{2\times -16}

t=\frac{-35\pm \sqrt{1225+25600}}{-32}

\implies t\approx -4.02\text{ or }t\approx 6.21

∵ Time cannot be negative,

Hence, after 6.21 seconds the ball will reach the ground.

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Answer:

B. Quadratic​​​​​​​​​​

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Is a 100% increase followed by a 33.33% decrease more or less than the number you started with
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more than the number you started with


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- Monica goes for a 60 minute bike ride each day in the summer. Let a rep
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Answer:

m = 60a

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m = Dependent Variable.

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For a = 3 days, m = 180 minutes

For a = 4 days, m = 240 minutes

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For a = 6 days, m = 360 minutes

For a = 7 days, m = 420 minutes

Step-by-step explanation:

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If a represents the number of days Monica rides her bike and m represents the total number of minutes she spends riding her bike, then a represents the independent variable and m represents the dependent variable.

The relation between a and m can be written as an equation, m = 60a.

Now, for a = 1 day, m = 60 minutes

For a = 2 days, m = 60 × 2 = 120 minutes

For a = 3 days, m = 60 × 3 = 180 minutes

For a = 4 days, m = 60 × 4 = 240 minutes

For a = 5 days, m = 60 × 5 = 300 minutes

For a = 6 days, m = 60 × 6 = 360 minutes

For a = 7 days, m = 60 × 7 = 420 minutes

Therefore, this is the table to show how many minutes Monica would ride her bike over the course of 1 week. (Answer)

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Answer:

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58 dollars (0.20) + 58 dollars

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