I need to know a system of equations to solve this please

Mathematics

1 answer:

Snowcat [4.5K]2 years ago

3 0

3.That BC are congruent and that AB and AC are congruent as well

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Abel and Cedric will share a total of $180. Abel will receive half as much as Cedric. What amount. in dollars, will Cedric recei

babymother [125]

Answer:

Abel receives $60, and Cedric receives $120

Step-by-step explanation:

Let Abel's share = A

Let Cedric's share = C

we are given the following

A + C = 180 - - - - - (1) (Abel and Cedric will share a total of $180)

$A = \frac{C}{2}\ - - - - - - - (2)$ (Abel will receive half as much as Cedric. )

from equation 2:

$A = \frac{C}{2}\\ C = 2A\ - - - - - - (3)$

putting this value of C in eqn (3) into eqn (1)

A + (2A) = 180

3A = 180

∴ A = 180 ÷ 3 = 60

to find C, let us replace the value of A in eqn (3) with 60

C = 2A - - - - (3)

C = 2 × 60

C = 120

Therefore, Abel receives $60, and Cedric receives $120

5 0

2 years ago

There are 412 students and 20 teachers taking buses on a trip to a museum. Each bus can seat a maximum of 48. Which inequality g

-BARSIC- [3]

The inequality $\mathrm{b} \geq \frac{\text { total number of travelers }}{\text { capacity of each bus }}$ gives the least number of buses, b, needed for the trip. The least number of buses is 9

Solution:

Given that, There are 412 students and 20 teachers taking buses on a trip to a museum.

Each bus can seat a maximum of 48.

We have to find which inequality gives the least number of buses, b, needed for the trip?

Now, there are 412 students and 20 teachers, so in total there are 412 + 20 = 432 travelers

The number of buses required “b” is given as:

$\text { (b) } \geq \frac{\text { total number of travelers }}{\text { capacity of each bus }}$

$\text { So, number of buses required } \geq \frac{432}{48}$

Number of buses required ≥ 9 buses.

But least number will be 9 from the above inequality.

Hence, the inequality $\mathrm{b} \geq \frac{\text {total number of travelers}}{\text {capacity of each bus}}$ gives least count of busses and least count is 9.