Answer:
G. y=2x-5
Step-by-step explanation:
First, find the slope from 2x-y=-3
-y=-2x-3
y=2x+3, which means that the slope is 2
Since it is parallel, the given equation and the line we are finding has the same slope.
let y=mx+b, where m=2, y=5, x=5
5=2(5)+b
5=10+b
-5=b
Thus, y=2x-5
Answer:
1/sqrt10
Step-by-step explanation:
1) Find out cosA using formula (cosA)^2+(sinA)^2=1
The module of cosA= sqrt (1- (-3/5)^2)= sqrt 16/25=4/5
So cosA=-4/5 or cosA=4/5.
Due to the condition 270degrees< A<360 degrees, 0<cosA<1 that's why cosA=4/5.
2) Find sinA/2 using a formula cosA= 1-2sinA/2*sinA/2 where cosA=4/5.
(sinA/2)^2= 0.1
sinA= sqrt 0.1= 1/ sqrt10 or sinA= - sqrt 0.1= -1/sqrt10
But 270°< A< 360°, then 270/2°<A/2<360/2°
135°<A/2<180°, so sinA/2 must be positive and the only correct answer is
sin A/2= 1/sqrt10
Answer:
the answer is 2.
Step-by-step explanation:
How do I know this? well, those red arrows on the line show that those 2 sides (ED) and (AB) are congruent which means they are equal. therefore if they are equal and we know ED is 2, then we know AB is also 2. Hope this helped :)
I think the answer is one solution
Answer:
The answer would be 28
Step-by-step explanation:
You would plug 8 in where k is and 2 where j is
so (8)3 - 4(2) +12
answer is 28
