A12×p78<br><br> please help idk this

A medical researcher wondered if there is a significant difference between the mean birth weight of boy and girl babies. Random

Yuliya22 [10]

Answer:

b) independent samples t-test

$t=\frac{(5.92 -5.74)-(0)}{\sqrt{\frac{1.88^2}{5}}+\frac{1.81^2}{5}}=0.154$

$p_v =2*P(t_{8}>0.154) =0.881$

So with the p value obtained and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (boys) is NOT significantly different than the mean for the group 2 (Girls).

Step-by-step explanation:

The system of hypothesis on this case are:

Null hypothesis: $\mu_1 = \mu_2$

Alternative hypothesis: $\mu_1 \neq \mu_2$

Or equivalently:

Null hypothesis: $\mu_1 - \mu_2 = 0$

Alternative hypothesis: $\mu_1 -\mu_2\neq 0$

Our notation on this case :

$n_1 =5$ represent the sample size for group 1

$n_2 =5$ represent the sample size for group 2

We can calculate the mean and deviation for eaach group with the following formulas:

$\bar X= \frac{\sum_{i=1}^n X_i}{n}$

$s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$\bar X_1 =5.92$ represent the sample mean for the group 1

$\bar X_2 =5.74$ represent the sample mean for the group 2

$s_1=1.88$ represent the sample standard deviation for group 1

$s_2=1.81$ represent the sample standard deviation for group 2

If we see the alternative hypothesis we see that we are conducting a bilateral test and with independnet samples t test.

b) independent samples t-test

The statistic is given by this formula:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{\sqrt{\frac{s^2_1}{n_1}}+\frac{S^2_2}{n_2}}$

And now we can calculate the statistic:

$t=\frac{(5.92 -5.74)-(0)}{\sqrt{\frac{1.88^2}{5}}+\frac{1.81^2}{5}}=0.154$

The degrees of freedom are given by:

$df=5+5-2=8$

And now we can calculate the p value using the altenative hypothesis:

$p_v =2*P(t_{8}>0.154) =0.881$

So with the p value obtained and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (boys) is NOT significantly different than the mean for the group 2 (Girls).

7 0

3 years ago

You gave the server at a restaurant a 22% tip and ended up paying $41.48. What was the price of your meal before you applied the

const2013 [10]

Answer: The price of meal before the tip = $34.

Step-by-step explanation:

Given : The percentage of tip = 22% = 0.22 ( we divide a percentage by 100 to convert it into decimal)

Total amount paid ( including tip) = $41.48

Formula for Total bill = Price of meal + Tip amount , where Tip amount= 22% of Price of meal.

Let x be the price of meal, then

Total bill =x + 0.22 x (x )

⇒ $41.48= x(1+0.22) [ By distributive property]

⇒ $41.48 = x (1.22)

⇒ x= ($41.48) ÷ 1.22

⇒ x= 34

Hence, the price of your meal before you applied the tip = $34.

7 0

3 years ago

I cannot understand this can you guys help

igor_vitrenko [27]

The mean is not the same thing as median
mean=78+81+85+87=331
mean=331/4=82.75
median is the middle number, but you have a par set of numbers, so your median will be the middle numbers 78,81,85,87 , which are 81+85=166, 166/2=83
83 is your median

5 0

3 years ago

PLEASE ANSWER!! I WILL GIVE BRAINIEST TO WHOEVER ANSWERS THIS FIRST!!!!!!!!!!!!!!!!!!!!!!!!!!!

hammer [34]

96 Square inches because if you multiply every side with each length you get 96 in2

6 0

3 years ago

Read 2 more answers

Which statements could you use to conclude that JKLM is a parallelogram?

telo118 [61]

Angle JML Angle LKJ & Angle MJK = MLK

Why it's correct:

In a parallelogram the opposite angles are congruent (as well as the opposite sides

7 0