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The life of a semiconductor laser at a constant power is normally distributed with a mean of 7,000 hours and a standard deviation of 600 hours. If three lasers are used in a product and they are assumed to fail independently, the probability that all three are still operating after 7,000 hours is closest to? Assuming percentile = 95%
Answer:
0.125
Step-by-step explanation:
Assuming for 95%
z score for 95th percentile = 1.645
We find the Probability using z table.
P(z = 1.645) = P( x ≤ 7000)
= P(x<Z) = 0.95
After 7000 hours = P > 7000
= 1 - P(x < 7000)
= 1 - 0.95
= 0.05
If three lasers are used in a product and they are assumed to fail independently, the probability that all three are still operating after 7,000 hours is calculated as:
(P > 7000)³
(0.05)³ = 0.125
Answer:
144
Step-by-step explanation:
Answer:
C i think
Step-by-step explanation:
Answer: Total cost/month = 7 + 3x
Step-by-step explanation:
This is only the total cost per month that is why it is only 7 and 3x since the number of downloaded games is not given.
I'm not sure about my answer but I hope that it helps.
Answer:
Ano bayan puro Math nalang nakikita ko
