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3 years ago

Write a slope intercept equation for a line passing through the given point perpendicular to a line

1 answer:

4 0

Hello :
 a slope intercept equation is : y - b = s (x - a )
passing through the given point A( a , b) and the slope : s when : s×s' = -1
s' : the slope of The other line .

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What is the quotient of 6/9 divided 1/3

NeTakaya

18/9, or 2/1. OR you can write that as 2

3 0

3 years ago

Read 2 more answers

G(x)= -2x-7 what is g(-3) A. -13 B. -1 C. -6 D. 6

True [87]

You plug -3 into -2x-7 and you get B -1.

4 0

3 years ago

Read 2 more answers

Simplify. Your answer should contain only positive exponents with no fractional exponents in the denominator.

mart [117]

Answer:

$\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}$ .

Step-by-step explanation:

The given expression is

$\dfrac{3y^{\frac{1}{4}}}{4x^{-\frac{2}{3}}y^{\frac{3}{2}}\cdot 3y^{\frac{1}{2}}}$

We need to simplify the expression such that answer should contain only positive exponents with no fractional exponents in the denominator.

Using properties of exponents, we get

$\dfrac{3}{4\cdot 3}\cdot \dfrac{y^{\frac{1}{4}}}{x^{-\frac{2}{3}}y^{\frac{3}{2}+\frac{1}{2}}}$ $[\because a^ma^n=a^{m+n}]$

$\dfrac{1}{4}\cdot \dfrac{y^{\frac{1}{4}}}{x^{-\frac{2}{3}}y^{2}}$

$\dfrac{1}{4}\cdot \dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{y^{2}}$ $[\because a^{-n}=\dfrac{1}{a^n}]$

$\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}$

We can not simplify further because on further simplification we get negative exponents in numerator or fractional exponents in the denominator.

Therefore, the required expression is $\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}$ .

5 0

4 years ago

10. Five is 20% of what number?

balu736 [363]

Answer:

Step-by-step explanation:

20*5=100%

then you multiply 5 by 5 giving you 25

4 0

3 years ago

There are two sizes of red and blue marbles in a box. If the big marbles in the box, 45 are red and 3/4 are blue. The fraction o

Nat2105 [25]

Let
x------> amount of big marbles in the box
y------> amount of small marbles in the box
R----> amount of small marbles that are red in the box
B----> amount of small marbles that are blue in the box

we know that
x=45+(3/4)*x----> x-(3/4)*x=45----> x/4=45-----> x=180

R+B=y-----> equation 1
R=(2/5)*y---> equation 2
B=(3/5)*y---> equation 3
B=R+24----> equation 4

substitute equation 2 in equation 1
[(2/5)*y]+B=y----> equation 5

substitute equation 2 in equation 4
B=[(2/5)*y]+24----> equation 6

resolve the system
[(2/5)*y]+B=y---> multiply by 5----> 2y+5B=5y----> 3y=5B
B=[(2/5)*y]+24----> multiply by 5----> 5B=2y+120

using a graph tool
see the attached figure

the solution is
B=72
y=120
R=y-B----> R=48

total marbies=x+y-----> 180+120-----> 300
tota; big marbies=180
percent of the marbles are big marbles
if 100%-----------> 300
X----------------> 180
x=180*100/300-----> x=60%

the answer is
60%

8 0

3 years ago