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Oxana [17]
3 years ago
7

g A catering service offers 7 %E2%80%8b Appetizers, 9 main%E2%80%8B courses, and 5 desserts. A banquet committee is to select 2

%E2%80%8b Appetizers, 8 main%E2%80%8B courses, and 4 desserts. How many ways can this be%E2%80%8B done
Mathematics
1 answer:
Feliz [49]3 years ago
5 0

Answer:

945 ways

Step-by-step explanation:

<u>Total</u>

  • Number of Appetizers = 7
  • Number of main courses = 9
  • Number of desserts =5

<u>Required Selection</u>

  • Number of Appetizers = 2
  • Number of main courses = 8
  • Number of desserts =4

2  Appetizers out of 7 can be selected in ^7C_2 ways

8 main courses out of 9 can be selected in ^9C_8 ways

4 desserts out of 5 can be selected in ^5C_4 ways

Therefore, the number of ways this can be done

=^7C_2 \times ^9C_8 \times ^5C_4

=945 ways

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4 years ago
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Step-by-step explanation:

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Please answer this question now
liubo4ka [24]

Answer:

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Step-by-step explanation:

Step 1

We find the third angle

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Third angle = Angle V = 180° - (63 + 50)°

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Step 2

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Cross Multiply

sin 50 × 37 = v × sin 63

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To find the area of triangle VWX

We use heron formula

= √s(s - v) (s - w) (s - x)

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s = (38.22 + 37 + 31.81)/2

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Area of the triangle = √53.515× (53.515 - 38.22) × (53.515 - 37 ) × (53.515 - 31.81)

Area of the triangle = √293402.209

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