<h2><em>What is (2/x^2)^3 reduced to simplest form ?</em></h2>
<em>A. 8x^-6 </em>
<em>B. 8x^6</em>
<em> C. 6/x^6</em>
<em> <u>D. 8/ x^6</u></em>
<em><u>hope </u></em><em><u>it</u></em><em><u> helps</u></em>
Answer:
a
Step-by-step explanation:
r = 2.5 in
V = 4(3.14)
/3 = 
Answer:
--- Running cost
--- Monthly income
71 cars
R1775
Step-by-step explanation:
Given
Expenses

per car
Income
per car
Solving (a): Expression for the running cost
This is calculated as:

Where
y = Total running cost
x = number of cars
So:


Solving (b): Expression for monthly income
This is calculated as:

Where
y = Total income
x = number of cars
So:


Solving (c): Break even
To do this, we equate the expressions in (a) and (b)


Collect Like Terms


Solve for x


Solving (d): How much to break even
Substitute 71 for x in any of (a) or (b)



<em>Solving (e): There is no question to answer on the "graph"</em>
Y = f(x) = 8x^2 - 2x + 3
a.) dy/dx = 16x - 2
b.) dy = (16x - 2)dx
dy = (16(2) - 2)(2 - 1.97) = 0.03(32 - 2) = 0.03 * 30 = 0.9
dy = 0.9
c.) (8(2)^2 - 2(2) + 3) - (8(1.97)^2 - 2(1.97) + 3) = 31 - 30.1072 = 0.8928
Δy = 0.8928
Answer:
True
Step-by-step explanation:
Confidence interval for banking service in a given confidence level can be calculated as M±ME where
- M is the mean banking service in the sample and
- ME is the Margin of Error
margin of error (ME) is calculated using the formula
ME=
where
- t is the corresponding statistic in the given confidence level
- s is the standard deviation of the sample(or of the population if it is known)
t-statistic for 99% confidence level is always bigger than 95% confidence level which makes Margin of Error bigger and thus confidence interval wider.