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AveGali [126]
2 years ago
5

Write 25/4 as mixed number give your answer in its simplest from​

Mathematics
1 answer:
Sedaia [141]2 years ago
3 0

in decimal= 6.25

hope it helped you

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Write2.1 as a mixed number and as an improper fraction.<br> Do not try to simplify your answers.
Elden [556K]

Answer:

2 1/10 and 21/10

Step-by-step explanation:

2.1 is 2 + 0.1 when expanded.

2 is just 2 and then 0.1 as a fraction is 1/10. The mixed number would be                 2 1/10.

The improper fraction  is just 21/10 (convert the mixed number into improper form).

Converting from mixed number to improper: <u>Multiply the number in the front (in this case 2) by the denominator. </u>

<u />

<u>That is 2 x 10 which is 20. Then add that number (20) to the numerator. 20 + 1 is equal to 21. </u>

<u />

<u>21 would be our numerator and the denominator would stay the same (10). </u>

21/10 is the improper form.

8 0
2 years ago
What’s the correct answer for this ?
icang [17]

Answer:

D.

Step-by-step explanation:

Since both the triangles as kept separately are similar, so we'll take proptionality of their sides to find one side

MP/ML=MN/MK

20/28=35/MK

CROSS MULTIPLYING

20×MK=28×35

MK=980/20

MK=49

5 0
2 years ago
Helppp meeeeeeeeeeeeeeee
postnew [5]

Answer:

Area = 168m^2

Step-by-step explanation:

Area of triangle = 1/2×base×height

Area = 1/2bh

= 1/2(8+16)(14)

= 168m^2

7 0
2 years ago
Leila's father used six-tenths of a full tank of gasoline on their trip. Nine gallons were used.
Bad White [126]

Answer:

15

Step-by-step explanation:

if 6/10 = 9 gal. then we can divide 9 by 6 and then multiply that answer by ten

5 0
3 years ago
Conplete the square to solve the quadratic equation. x<br><img src="https://tex.z-dn.net/?f=1%20%7Bx%7D%5E%7B2%7D%20%20-%206x%20
o-na [289]

Answer:

\large\boxed{x=4\pm2\sqrt6}

Step-by-step explanation:

x^2-6x+12=2x+20\qquad\text{subtract}\ 2x\ \text{and}\ 12\ \text{from both sides}\\\\x^2-8x=8\\\\x^2-2(x)(4)=8\qquad\text{add}\ 4^2=16\ \text{to both sides}\\\\x^2-2(x)(4)+4^2=8+4^2\qquad\text{use}\ (a-b)^2=a^2-2ab+b^2\\\\(x-4)^2=24\iff x-4=\pm\sqrt{24}\\\\x-4=\pm\sqrt{4\cdot6}\\\\x-4=\pm\sqrt4\cdot\sqrt6\\\\x-4=\pm2\sqrt6\qquad\text{add 4 to both sides}\\\\x=4\pm2\sqrt6

6 0
2 years ago
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