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Andre45 [30]
4 years ago
9

What is the largest number of consecutive integers whose sum is 2003?

Mathematics
1 answer:
Sladkaya [172]4 years ago
4 0
2003 \div 2=1001.5

Go .5 below and .5 above this answer to get your consecutive integers.

Therefore the answer is 1001 and 1002.
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Find the limit a b c d or e
Brums [2.3K]
f(x)=-x^2-4;\ g(x)=2x\\\\g(f(x))=g(-x^2-4)=2(-x^2-4)=-2x^2-8\\\\\lim\limits_{x\to5}g(f(x))=\lim\limits_{x\to5}(-2x^2-8)=(*)\\\\\text{substitute the value of x=5}\\\\(*)=-2\cdot5^2-8=-58\to B.
5 0
3 years ago
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While playing a game, you move 5 steps forward and then 11 steps backward. Write each number as an integer
MaRussiya [10]
To represent 5 steps forward as an integer, you would write 5 or +5. Forward is a positive movement.

11 steps backward would be -11 because moving backwards would be the opposite of moving forward (+).
7 0
3 years ago
According to the lecture, a valedictory speech should last approximately ________ minutes.
fiasKO [112]
<span>According to the lecture, a valedictory speech should last approximately 15 minutes. </span>
6 0
3 years ago
Find and of the function = − −( − ).​
Ivan

Answer:

Thats not possible

Step-by-step explanation:

There is no:

  • numbers
  • variables
  • only negative signs
8 0
3 years ago
The potential in a region between x = 0 and x = 6.00 m is V = a + bx, where a = 15.4 V and b = -5.10 V/m.
Minchanka [31]

Answer:

V(0)=15.4\\V(3)=0.1\\V(6)=-15.2

Step-by-step explanation:

The potential in a region between x = 0 and x = 6.00 m is V = a + bx.

Put a = 15.4 V and b = -5.10 V/m.

So, V=15.4-5.10x

To find: Potential at x =0, 3, 6

Solution:

Potential at x = 0:

V=15.4-0=15.4

Potential at x = 3:

V=15.4-5.10(3)=15.4-15.3=0.1

Potential at x = 6:

V=15.4-5.10(6)=15.4-30.60=-15.2

Therefore,

V(0)=15.4\\V(3)=0.1\\V(6)=-15.2

7 0
4 years ago
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