What is the largest number of consecutive integers whose sum is 2003?
1 answer:
=1001.5
Go .5 below and .5 above this answer to get your consecutive integers.
Therefore the answer is 1001 and 1002.
You might be interested in
Answer:
Add by 4
Step-by-step explanation:
-3+4=1
1+4=5
5+4=9
9+4=13
33.3% is the answer, I think
20/60 ---> 1/3, covert this to a percentage and it equals 33.3%
Answer:
a -2b
Step-by-step explanation:
2(a+2b)-a-2b
Distribute
2a+4b -a-2b
Combine like terms
a -2b
6 3/4=6*4+3/4=24+3/4=27/4
z/12=27/4
4z=27*12
4z=324
z=81
