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insens350 [35]
2 years ago
13

A.) 15.7in B.) 31.4in C.) 40in D.) 62.8in

Mathematics
2 answers:
mina [271]2 years ago
5 0
B: 31.4in



hope this helps lol
IrinaK [193]2 years ago
4 0

Answer:

31.4 in

Step-by-step explanation:

This is a tricky question,

if you observe the shape carefully, you will notice that if you mirror (flip outward) each curve surface of each quardrant, what you will end up with is a complete circle with a radius of 5 inches.

Hence the combined length of all the curved surfaces is simply the circumference of the circle, given by:

Circumference = 2πr

= 2 x 3.14 x 5

= 31.4 in

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Answer:

$360. (I believe so, anyways.)

Step-by-step explanation:

Original Price x Discount % / 100

Discount = 600 × 40/100

 24000/100

$600 - $240

Final Price = $360

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Is the underlined verb in the sentence regular or irregular?  We arrived early to our football game last night.   A. irregular  
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Regular verb in that sentence
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At the science fair, Tanvi uses 8 fluid ounces of vinegar to make her volcano erupt. How many times can she make her volcano eru
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4 times

Step-by-step explanation:

1 quart is equivalent to 32 fluid ounces.

If each eruption consumes 8 fluid ounces of vinegar. Assuming that the amount of vinegar required per eruption is constant, the number of times Tanvi can make her volcano erupt is:

n=\frac{32}{8}\\n=4\ times

Tanvi can make her volcano erupt 4 times  with 1 quart of vinegar.

7 0
3 years ago
A yard cleanup service charges a $345 fee plus $16.25 per hour. Another cleanup service charges a $213 fee plus $24.50 per hour.
Thepotemich [5.8K]

The time for the job for which the two company are the same is 16

<h3>How to form the equation and find the cost?</h3>

A yard cleanup service charges a $345 fee plus $16.25 per hour. Therefore,

using linear equation,

y = mx + c

where

  • y = total cost
  • x = time

Therefore,

y = 345 + 16.25x

Another cleanup service charges a $213 fee plus $24.50 per hour. Therefore,

y = 213 + 24.50x

Hence, the time when both cost are the same is as follows;

213 + 24.50x =  345 + 16.25x

213 - 345 = 16.25x - 24.50x

-132 = -8.25x

x = 132 / 8.25

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4 0
2 years ago
​41% of U.S. adults have very little confidence in newspapers. You randomly select 10 U.S. adults. Find the probability that the
lys-0071 [83]

Answer:

a) 0.2087 = 20.82% probability that the number of U.S. adults who have very little confidence in newspapers is exactly​ five.

b) 0.1834 = 18.34% probability that the number of U.S. adults who have very little confidence in newspapers is at least​ six.

c) 0.3575 = 35.75% probability that the number of U.S. adults who have very little confidence in newspapers is less than four.

Step-by-step explanation:

For each adult, there are only two possible outcomes. Either they have very little confidence in newspapers, or they do not. The answers of each adult are independent, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

​41% of U.S. adults have very little confidence in newspapers.

This means that p = 0.41

You randomly select 10 U.S. adults.

This means that n = 10

(a) exactly​ five

This is P(X = 5). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 5) = C_{10,5}.(0.41)^{5}.(0.59)^{5} = 0.2087

0.2087 = 20.82% probability that the number of U.S. adults who have very little confidence in newspapers is exactly​ five.

(b) at least​ six

This is:

P(X \geq 6) = P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 6) = C_{10,6}.(0.41)^{6}.(0.59)^{4} = 0.1209

P(X = 7) = C_{10,7}.(0.41)^{7}.(0.59)^{3} = 0.0480

P(X = 8) = C_{10,8}.(0.41)^{8}.(0.59)^{2} = 0.0125

P(X = 9) = C_{10,9}.(0.41)^{9}.(0.59)^{1} = 0.0019

P(X = 10) = C_{10,10}.(0.41)^{10}.(0.59)^{0} = 0.0001

Then

P(X \geq 6) = P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10) = 0.1209 + 0.0480 + 0.0125 + 0.0019 + 0.0001 = 0.1834

0.1834 = 18.34% probability that the number of U.S. adults who have very little confidence in newspapers is at least​ six.

(c) less than four.

This is:

P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.41)^{0}.(0.59)^{10} = 0.0051

P(X = 1) = C_{10,1}.(0.41)^{1}.(0.59)^{9} = 0.0355

P(X = 2) = C_{10,2}.(0.41)^{2}.(0.59)^{8} = 0.1111

P(X = 3) = C_{10,3}.(0.41)^{3}.(0.59)^{7} = 0.2058

So

P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0051 + 0.0355 + 0.1111 + 0.2058 = 0.3575

0.3575 = 35.75% probability that the number of U.S. adults who have very little confidence in newspapers is less than four.

5 0
3 years ago
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