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Marina86 [1]
3 years ago
6

Sharyn needs 3 3/8 yards of fabric to make a dress for herself and 2 1/8 yards of the same fabric to make a matching dress for h

er daughter. If she buys 6 1/8 yards of fabric, how much will she have left over?
Mathematics
2 answers:
notka56 [123]3 years ago
5 0
6 1/8 - (3 3/8 + 2 1/8) = 
6 1/8 - (5 4/8) =
5 9/8 - 5 4/8 =
5/8 yds <=== 
luda_lava [24]3 years ago
4 0

Answer:

\frac{5}{8} yards.

Step-by-step explanation:

We have been given that Sharyn needs 3 3/8 yards of fabric to make a dress for herself and 2 1/8 yards of the same fabric to make a matching dress for her daughter.

To find the yards of fabric left, we will subtract sum of yards used for both dresses from total fabric.

6\frac{1}{8}-(3\frac{3}{8}+2\frac{1}{8})

Convert mixed fractions into improper fractions:

\frac{6\times 8+1}{8}-(\frac{3\times8+3}{8}+\frac{2\times8+1}{8})

\frac{49}{8}-(\frac{27}{8}+\frac{17}{8})

Since denominators are equals, so we will combine numerators as:

\frac{49}{8}-(\frac{27+17}{8})

\frac{49}{8}-\frac{44}{8}

\frac{49-44}{8}

\frac{5}{8}

Therefore, Sharyn has \frac{5}{8} yards of fabric left.

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Emily and Miranda are standing outside. Emily is 5 feet tall and casts a shadow of 28 inches. Miranda’s shadow is 29.4 how tall
umka21 [38]
Miranda is 5 feet and 25 centimeters tall or 5.25.
So first I did 28/5=5.6
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Solve 20x + 5y = 15 for y<br>​
luda_lava [24]

Answer:

Step-by-step explanation:

20x+5y=15

Subtract 20x from both sides.

5y=15−20x

Divide both sides by 5.

__5y_  = _15-20x_____

    5                5

y=  __15-20______

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7 0
3 years ago
!!!*RIGHT ANSWER GETS BRAINLIEST!!!* Show that binomial is factor of the polynomial, then factor completely. r(x)=x^3-37x+84; x+
sladkih [1.3K]
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The question says solve for x Express as exact roots
bezimeni [28]

Solve for x

\begin{gathered} 6x^2-11x=10 \\ 6x^2-11x-10=0 \end{gathered}

Let's solve the equation step-by-step.

6x^2-11x-10=0

For this equation: a=6, b=-11, c= -10

Step 1: Use quadratic formula with a=6, b=-11, c=-10.

\begin{gathered} x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\  \\  \\ x=\frac{-(-11)\pm\sqrt[]{(-11)^2^{}-4\times6\times-10}}{2\times6} \\  \\ x=\frac{11\pm\sqrt[]{361}}{12} \\  \\ x=\frac{5}{2\text{ }}\text{ or x=}-\frac{2}{3} \end{gathered}

Answer

x=\frac{5}{2\text{ }}\text{ or x=}-\frac{2}{3}

5 0
1 year ago
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