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3 years ago

Find 3 different ratios that are equivalent 7:3 explain why these ratios are equivalent

Mathematics

1 answer:

kkurt [141]3 years ago

6 0

Answer:

7:3, 14:6, 28:12

multiples.. hope that helps.

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Which of the following complete the proof above?

svp [43]

Answer:

(A)

Step-by-step explanation:

To be honest, since all of them are different, as long as you get the first one right, you will get the others right. A is your answer, for the following reasons:

Reflexive Property: The Reflexive property states that the mirrored version of itself will always be congruent with itself. Generally, to make it easier, they will write it opposite (as they did in the given proof):

<em>line</em> AC ≅ <em>line</em> CA

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3 years ago

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Anna saves 3 dollars for every 10 dollars she earns.Patrick saves 5 dollars for every 20 dollars he earns.Do the two save money

NNADVOKAT [17]

The two do not save money at the same rate, because if you make common denominators of 20, Anna saves 6 dollars for every 20, while Patrick only saves 5 dollars for every twenty earned. So, Anna ends up saving more than Patrick.

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3 years ago

A submarine left Diego Garcia five hours before a cruise ship. The ships traveled in opposite directions. The cruise ship travel

Rina8888 [55]

Answer:

The speed of the submarine is 15.429 miles per hour.

Step-by-step explanation:

Let suppose that both ships travel at constant velocities. As we know that both travel in opposite directions, it is supposed that cruise ship moves in +x direction, whereas submarine in -x direction. Kinematic equations for each sheep are described below:

Ship

$x_{Sh} = x_{o} + v_{Sh}\cdot t$

Submarine

$x_{Su} = x_{o}+v_{Su}\cdot t$

Where:

$x_{o}$ - Position of Diego Garcia island, measured in miles.

$x_{Sh}$ , $x_{Su}$ - Current positions of ship and submarine, measured in miles.

$v_{Sh}$ , $v_{Su}$ - Velocities of ship and submarine, measured in miles per hour.

$t$ - TIme, measured in hours.

If we know that $x_{Sh} - x_{Su} = 241\,mi$ , $v_{Sh} = 19\,\frac{mi}{h}$ and $t = 7\,h$ , then:

$x_{Sh} - x_{Su} = (v_{Sh}-v_{Su})\cdot t$

We clear now the velocity of submarine:

$\frac{x_{Sh}-x_{Su}}{t} = v_{Sh}-v_{Su}$

$v_{Su} = v_{Sh}-\frac{x_{Sh}-x_{Su}}{t}$

$v_{Su} = 19\,\frac{mi}{h} -\frac{241\,mi}{7\,h}$

$v_{Su} = -15.429\,\frac{mi}{h}$

Speed of the submarine is the magnitude of its velocity, which is 15.429 miles per hour.

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3 years ago

Please Help! i am on the last stretch for a test, and i seriously need help with this question. i know its lame, but i really am

Romashka-Z-Leto [24]

I believe that it's A neither, because I don't think that it could be displayed on a coordinate graph when it has an exponent in it. So I think it's A. Let me know if I'm correct. ;-)

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2 years ago

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Find the area of the semicircle. Round your answer to the nearest hundredth. YEAH IVE BEEN STUCK ON THIS help please I need the

aivan3 [116]

Answer:

your answer will be 127.17 sq in

Step-by-step explanation:

hope it helps you

have a wonderful day!!!

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3 years ago

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