Answer:
Step-by-step explanation:
y = -2x + 2/2.....slope = -2, y int = 2/2(or just 1)
y = -2x + 3/2....slope = -2, y int = 3/2
when the equations have the exact same slope, but different y intercepts.....and this one does....then there is no solution because these are parallel lines....they never cross each others path.
<em><u>Option A</u></em>
<em><u>The solution is:</u></em>
<em><u>Solution:</u></em>
We have to solve the equation f(x) = 0
Let f(x) = 0
Solve the above equation
Take square root on both sides
Thus the solution is found
Graph the feasible region for the following constraints: x + y < 5. 2x + y > 4 ... y = 10/3. x = 30/3 - 10/3 = 20/3. Intersects at (20/3, 10/3). -x + 2y = 0. x - 2y = 0.
hence i would go for
<span>(6,3)</span>
Solving for y:
4x-3y=10. (subtract 4x on both sides)
-3y=-4x+10. (divide by -3 on both sides)
y=4/3 x+10/3
<span> remainder is f(3) </span>
<span>3^3 - 6*3^2 - 9*3 + 3 </span>
<span>= 27 - 54 - 27 + 3 </span>
<span>= -51</span>
