B. C=250+(17.50s) C.c=250+(17.50s)<span> Last one you do 1000-250=750/17.50=41 students can go. I did this because you have a budget of 1000 and 250 already on the bus. So 1000-250=750. And the rest of the money is for science students!</span>
You are looking for three consecutive integers whose sum is 93. First, divide 93 by 3 and get 31. Go one above 31 and one below. You get 30, 31 and 32 which sum to 93.