3 years ago

Find the slope-intercept form of a line that goes through the point (-1,3) and is parallel to -x+3y=12

1 answer:

6 0

First, I would simplify the given equation to find the slope of the parallel line as it will be the same for the line we are looking for.
3y=x+12
y=(x/3)+4

Slope= 1/3

Our equation now looks close, but we need the intercept.
y=(x/3)+B

Plug in the given point to find the intercept.
3=(-1/3)+B
4/3=B

Plug all the known values into the equation to complete the slope-intercept form.
y=(x/3)+4/3

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3 years ago

Slope is -2 and y-intercept is -6 how do I write the linear equation in slope intercept form

PtichkaEL [24]

You need to write it in the form y = mx +b
since slope is m and b is the y-intercept, it would be written as y = -2x + -6

I hope this helped :)

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