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IrinaK [193]
3 years ago
6

Find the slope-intercept form of a line that goes through the point (-1,3) and is parallel to -x+3y=12

Mathematics
1 answer:
Aliun [14]3 years ago
6 0
First, I would simplify the given equation to find the slope of the parallel line as it will be the same for the line we are looking for.
3y=x+12
y=(x/3)+4

Slope= 1/3

Our equation now looks close, but we need the intercept.
y=(x/3)+B

Plug in the given point to find the intercept.
3=(-1/3)+B
4/3=B

Plug all the known values into the equation to complete the slope-intercept form.
y=(x/3)+4/3
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Lunna [17]
-\frac{1}{3}\left|1\cdot \left(\frac{1}{2}\right)^2\right|-\frac{2}{3}-2^3-\frac{2}{3}\left|-\frac{1}{2}\right|^3
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