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3 years ago

Help me with this problem?

Mathematics

1 answer:

nignag [31]3 years ago

4 0

Answer: $\frac{2x(5x+1)}{4x-1}$

Step-by-step explanation:

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Subtract:

choli [55]

Answer:

it's answer is D -92

As -57-19-16= -92

3 0

3 years ago

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9(x+3)=3(3x+6)+9 how many solutions?

Slav-nsk [51]

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$9(x +3) = 3(3x + 6) + 9$

$9x + 27 = 9x + 18 + 9$

$9x + 27 = 9x + 27$

The two sides of this equation are exactly the same, so the above equation holds for any value of x , thus we have infinite solution for it.

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8 0

3 years ago

A laboratory scale is known to have a standard deviation (sigma) or 0.001 g in repeated weighings. Scale readings in repeated we

weqwewe [10]

Answer:

99% confidence interval for the given specimen is [3.4125 , 3.4155].

Step-by-step explanation:

We are given that a laboratory scale is known to have a standard deviation (sigma) or 0.001 g in repeated weighing. Scale readings in repeated weighing are Normally distributed with mean equal to the true weight of the specimen.

Three weighing of a specimen on this scale give 3.412, 3.416, and 3.414 g.

Firstly, the pivotal quantity for 99% confidence interval for the true mean specimen is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean weighing of specimen = $\frac{3.412+3.416+3.414}{3}$ = 3.414 g

$\sigma$ = population standard deviation = 0.001 g

n = sample of specimen = 3

$\mu$ = population mean

Here for constructing 99% confidence interval we have used z statistics because we know about population standard deviation (sigma).

So, 99% confidence interval for the population mean, $\mu$ is ;

P(-2.5758 < N(0,1) < 2.5758) = 0.99 {As the critical value of z at 0.5% level

of significance are -2.5758 & 2.5758}

P(-2.5758 < $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ < 2.5758) = 0.99

P( $-2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ < ${\bar X - \mu}$ < $2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.99

P( $\bar X-2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.99

99% confidence interval for $\mu$ = [ $\bar X-2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ , $\bar X+2.5758 \times {\frac{\sigma}{\sqrt{n} } }$ ]

= [ $3.414-2.5758 \times {\frac{0.001}{\sqrt{3} } }$ , $3.414+2.5758 \times {\frac{0.001}{\sqrt{3} } }$ ]

= [3.4125 , 3.4155]

Therefore, 99% confidence interval for this specimen is [3.4125 , 3.4155].

6 0

3 years ago

Write an equation to represent each situation.

mina [271]

Answer:

18 years

Step-by-step explanation:

2(8+x) = 34+x

16+2x = 34+x

-18 = -x

4 0

3 years ago

Wendy purchased 9 pizzas for x dollars. She spent a total of $85.50. Find the value of x

disa [49]

X=9.5 all you do is divide the total by the other factor you have

5 0

3 years ago

Read 2 more answers