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kotegsom [21]
3 years ago
15

Emily can ride her scooter 18 miles in 50 minutes. a)how long would it take for her to ride 4 miles? b)what is her unit rate in

miles per hour?
Mathematics
1 answer:
Blizzard [7]3 years ago
5 0

Answer:A) At this same rate (speed) how far can she ride in two hours?

B) how long would it take for her to ride 4 miles?

C) what is her unit rate in miles per hour?

Step-by-step explanation:pls mark me as brainest pls

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Billy’s gave his dad 1/2 of his cookie. How much did billy have left to eat
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Read 2 more answers
Imaginá que tenés 125 dados cúbicos del mismo tamaño ¿Cuantos dados de altura tiene el cubo de mayor tamaño que podés armar apil
kumpel [21]

Answer:

(i) Debemos apilar 5 dados para construir el cubo de mayor tamaño.

(ii) Se necesita 121 dados cuadrados para formar el cuadrado con la mayor cantidad de dados posibles, quedando 4 dados sobrantes.

Step-by-step explanation:

(i) Sabemos por la Geometría Euclídea del Espacio que un cubo es un sólido regular con 6 caras cuadradas y longitudes iguales. Cada dado tiene un volumen de 1 dado cúbico y 125 dados dan un volumen total de 125 dados cúbicos.

El volumen de un cubo está dado por la siguiente fórmula:

V = L^{3}

Donde:

L - Longitud de la arista, medida en dados.

V - Volumen del cubo, medido en dados cúbicos.

Ahora, necesitamos despejar la longitud de la arista para calcular la altura máxima posible:

L = \sqrt[3]{V}

Dado que V = 125\,dados^{3}, encontramos que la altura del cubo de mayor tamaño sería:

L =\sqrt[3]{125\,dados^{3}}

L = 5\,dados

Debemos apilar 5 dados para construir el cubo de mayor tamaño.

(ii) El área cuadrada formada por cubos está determinada por la siguiente fórmula:

A = L^{2}

Donde:

L - Longitud de arista, medida en dados.

A - Área, medida en dados cuadrados.

Puesto que la longitud de arista se basa en un conjunto discreto, esto es, el número de dados disponibles, debemos encontrar el valor máximo de L tal que no supere 125 y de un área entera. Es decir:

L \leq 125\,dados

Si cada cubo tiene un área de 1 dado cuadrado, entonces un cuadrado conformado por 125 dados tiene un área total de 125 dados cuadrados. Entonces:

L^{2}< 125\,dados^{2}

Esto nos lleva a decir que:

L < 11.180\,dados

Entonces, la longitud máxima del cuadrado con la mayor cantidad de cubos posible es de 11 dados. El número total requerido de cubos es el cuadrado de esa cifra, es decir:

n = (11\,dados)^{2}

n = 121\,dados

Se necesita 121 dados cuadrados para formar el cuadrado con la mayor cantidad de dados posibles, quedando 4 dados sobrantes.

4 0
3 years ago
One month Ashley rented 2 movies and 5 video games for a total of $33. The next month she rented 8 movies and 3 video games for
Ray Of Light [21]

To answer this question, you should set up and equation before doing anything else. So for this question you 're going to set up two equations.

The first equation is 2x+5y=33

The second equation is 8x+3y=30

Once you do that you have to solve for either X or Y by canceling out the other one. In this problem figuring out the Y is easier because you can cancel the X's more easily than the Y. To cancel a variable, they have to add up to 0.

So to cancel the X you multiply the equation 2x+5y=33 by -4.

That gives you -8x-20y= -132

Then you set up the two equations and add them together.

(-8x-20y= -132) + (8x+3y=30)

That gives you -17y = -102

So then you solve for Y by dividing by -17. You find out that Y is equal to 6. Then you plug the 6 back into the ORIGINAL equations and solve for X, which turns out to be 1.5

Hope this helped and if you get confused or have questions please ask :)

6 0
3 years ago
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