Question

Can anyone help with this question pleasee

Answer 1

Answer:

$y = 1$

Step-by-step explanation:

Given:

$a^{3y - 5} = \frac{1}{a^2}$

Apply the negative exponent rule

$a^{3y - 5} = a^{-2}$

The bases will cancel each other

$3y - 5 = -2$

$3y - 5 + 5 = -2 + 5$

$3y = 3$

$\frac{3y}{3} = \frac{3}{3}$

$y = 1$