A.)5000.0085
.0-tenth place
.00-hundreth
.000-thousanth
Answer: No, the normal curve cannot be used.
Step-by-step explanation:
The theorem of the Normal approximation states that if X is B(n,p) then for large n X is N(np, np(1-p)).
The accuracy of this approximation is good
i. for n > [10/p(1-p)]
ii. p is close to 1/2
Hence given p= 4% = 0.04,
q = 1 - 0.04 = 0.96
Let N = [10/p(1-p)]
We find N = 10/p(1-p) = 10/(0.04× 0.96)
N ~= 260
Since n < 260 and p < 0.5
The approximation is not a good one
Answer:
The point is NOT on the line.
Step-by-step explanation:
Step 1: Write out equation
y = -x + 3
Step 2: Define point
A(6, 3)
x = 6, y = 3
Step 3: Plug in coordinates
3 = -(6) + 3
3 = -6 + 3
3 ≠ -3
Answer:
Zabato is thinking of 6
Step-by-step explanation:
I first set it up as an equation based on the word problem you have given me
(n + 10)3 = 8n
Distribute the 3
3n + 30 = 8n
Isolate n
3n - 8n +30 - 30 = 8n - 8n - 30
-5n = -30
-5n/-5 = -30/-5
n = 6
To check replace 6 with n
(6 + 10)3 = 8 (6)
(16)3 = 48
48 = 48
Answer:
135
Step-by-step explanation: 9x15=135