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4 years ago

Functions help?

Mathematics

1 answer:

Tcecarenko [31]4 years ago

6 0

Question A is a linear graph because it graphs as a diagonal line, while on the other hand Question B graphs as exponential! Hope this helped!

You might be interested in

Which statements about the line that passes through (−2, 0) and (2, −4) are true? Select all that apply.

inn [45]

Your question is incomplete.

Answer choices not apply.

But if this is your question in the picture below then this is your answer..

Answer:

The line intersects the y-axis at (0, −2).

The equation of the line is y = −x − 2.

The line intersects the x-axis at (−2, 0).

Step-by-step explanation:

6 0

3 years ago

2. Solve the system of equations. Write your answer in parametric vector notation. X, +5x2 + 4x3 + 3x4 +9xs = 18 2x, +6x2 + 4x3

ratelena [41]

Answer:

The system is inconsistent.

Step-by-step explanation:

The system is

$x_1+5x_2+4x_3+3x_4+9x_5=18\\2x_1+6x_2+4x_3+6x_4+6x_5=28\\3x_1+7x_2+4x_3+10x_4+x_5=41\\4x_1+6x_2+2x_3+7x_4+4x_5=29$

The associated matrix to the system is

$\left[\begin{array}{cccccc}1&5&4&3&9&18\\2&6&4&6&6&28\\3&7&4&10&1&41\\4&6&2&7&4&29\end{array}\right]$

Now we use row operations to find the echelon form of the matrix:

1. We substract to row 2, two times the row 1.

We substract to row 3, three times the row 1.

We substract to row 4, four times the row 1 and obtain the matrix

$\left[\begin{array}{cccccc}1&5&4&3&9&18\\0&-4&-4&0&-12&-8\\0&-8&-8&1&-26&-13\\0&-14&-14&-5&-32&-43\end{array}\right]$

2. We multiply the second row of the preview step by -1/4. We obtain the matrix

$\left[\begin{array}{cccccc}1&5&4&3&9&18\\0&1&1&0&3&2\\0&-8&-8&1&-26&-13\\0&-14&-14&-5&-32&-43\end{array}\right]$

We add to row 3, eight times the row 2.

We add to row 4, fourtheen times the row 2 and obtain the matrix

$\left[\begin{array}{cccccc}1&5&4&3&9&18\\0&1&1&0&3&2\\0&0&0&1&-2&3\\0&0&0&-5&10&-155\end{array}\right]$

4. We add to row 4 of the preview step, five times the row 3 and obtain the matrix

$\left[\begin{array}{cccccc}1&5&4&3&9&18\\0&1&1&0&3&2\\0&0&0&1&-2&3\\0&0&0&0&0&-140\end{array}\right]$

Using backward substitution we have that

$0x_5=-140$ , then $0=-140$ and this is absurd. Then The system is inconsistent.

4 0

4 years ago

Write an equation of the line that passes through (2 -5) and is parallel to the line 2y=3x+10

andrey2020 [161]

Step-by-step explanation:

Given equation is

2y = 3x + 10

3x - 2y + 10 = 0 .....i)

Any line parallel to line I) is

3x - 2y + k = 0 ......ii)

As the line two passes through the point ( 2 , - 5 ) Now substituting the values

3 * 2 - 2 * ( - 5) + k = 0

6 + 10 + k = 0

16 + k = 0

k = - 16

Now putting the value of k in equation two

3x - 2y + 16 = 0 is the required equation.

Hope it will help :)❤

8 0

3 years ago

3(-3a-1) what is the answer if you answer it correct you get 10 points

Mandarinka [93]

Answer: the best answer is 3(-3a-1)

Step-by-step explanation:

7 0

3 years ago

Simply your expression<br> 4[(12-2) ²÷4]

lina2011 [118]

Answer:

100

Step-by-step explanation:

Simplify the following:

4 (12 - 2)^2/4

Hint: | Express 4 (12 - 2)^2/4 as a single fraction.

4 (12 - 2)^2/4 = (4 (12 - 2)^2)/4:

(4 (12 - 2)^2)/4

Hint: | Cancel common terms in the numerator and denominator of (4 (12 - 2)^2)/4.

(4 (12 - 2)^2)/4 = 4/4×(12 - 2)^2 = (12 - 2)^2:

(12 - 2)^2

Hint: | Subtract 2 from 12.

| 1 | 2

- | | 2

| 1 | 0:

10^2

Hint: | Evaluate 10^2.

| 1 | 0

× | 1 | 0

| 0 | 0

1 | 0 | 0

1 | 0 | 0:

Answer: 100

8 0

3 years ago