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Anna71 [15]
3 years ago
15

Question 3, ame the angle pair 5 and 1 (in picture)

Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
3 0

Answer:

corresponding angels

hope it's helps you

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20.50 * 0.8 = $16.40

16.40 * 0.4 = $6.56

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Quadrilateral ABCD is transformed to create A′B′C′D′. Match the coordinates of A′ with the transformations that create it.
bulgar [2K]

Answer:

The answer is below

Step-by-step explanation:

From the image attached, the coordinates of point A is at (2, -4).

Transformation is the movement of a point from its initial location to a new position. Types of transformation include dilation, reflection, translation and rotation.

If a point A(x, y) is reflected over the x axis, the new point is at  A'(x, -y)

If a point A(x, y) is translated a units right and b units down, the new location is at A'(x + a, y - b)

If a point A(x, y) is dilated by  factor of a, the new location is at A'(ax, ay)

If a point A(x, y) is  rotated 180° clockwise about the origin, the new location is at A'(-x, -y)

Hence:

For Quadrilateral ABCD is reflected over the x-axis, the coordinates of A' is at A'(2, 4)

For Quadrilateral ABCD is translated 2 units right and 1 unit down, the coordinates of A' is at A'(4, -5)

For Quadrilateral ABCD is dilated by a scale factor of 3, the coordinates of A' is at A'(6, -12)

For Quadrilateral ABCD is rotated 180° clockwise about the origin the coordinates of A' is at A'(-2, 4).

Step-by-step explanation:

6 0
3 years ago
Identify an angle adjacent to the given angle.
Step2247 [10]
C.....hlj so yeah because it shows it on the diagram
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3 years ago
The angle of elevation from me to the top of a hill is 51 degrees. The angle of elevation from me to the top of a tree is 57 deg
julia-pushkina [17]

Answer:

Approximately 101\; \rm ft (assuming that the height of the base of the hill is the same as that of the observer.)

Step-by-step explanation:

Refer to the diagram attached.

  • Let \rm O denote the observer.
  • Let \rm A denote the top of the tree.
  • Let \rm R denote the base of the tree.
  • Let \rm B denote the point where line \rm AR (a vertical line) and the horizontal line going through \rm O meets. \angle \rm B\hat{A}R = 90^\circ.

Angles:

  • Angle of elevation of the base of the tree as it appears to the observer: \angle \rm B\hat{O}R = 51^\circ.
  • Angle of elevation of the top of the tree as it appears to the observer: \angle \rm B\hat{O}A = 57^\circ.

Let the length of segment \rm BR (vertical distance between the base of the tree and the base of the hill) be x\; \rm ft.

The question is asking for the length of segment \rm AB. Notice that the length of this segment is \mathrm{AB} = (x + 20)\; \rm ft.

The length of segment \rm OB could be represented in two ways:

  • In right triangle \rm \triangle OBR as the side adjacent to \angle \rm B\hat{O}R = 51^\circ.
  • In right triangle \rm \triangle OBA as the side adjacent to \angle \rm B\hat{O}A = 57^\circ.

For example, in right triangle \rm \triangle OBR, the length of the side opposite to \angle \rm B\hat{O}R = 51^\circ is segment \rm BR. The length of that segment is x\; \rm ft.

\begin{aligned}\tan{\left(\angle\mathrm{B\hat{O}R}\right)} = \frac{\,\rm {BR}\,}{\,\rm {OB}\,} \; \genfrac{}{}{0em}{}{\leftarrow \text{opposite}}{\leftarrow \text{adjacent}}\end{aligned}.

Rearrange to find an expression for the length of \rm OB (in \rm ft) in terms of x:

\begin{aligned}\mathrm{OB} &= \frac{\mathrm{BR}}{\tan{\left(\angle\mathrm{B\hat{O}R}\right)}} \\ &= \frac{x}{\tan\left(51^\circ\right)}\approx 0.810\, x\end{aligned}.

Similarly, in right triangle \rm \triangle OBA:

\begin{aligned}\mathrm{OB} &= \frac{\mathrm{AB}}{\tan{\left(\angle\mathrm{B\hat{O}A}\right)}} \\ &= \frac{x + 20}{\tan\left(57^\circ\right)}\approx 0.649\, (x + 20)\end{aligned}.

Equate the right-hand side of these two equations:

0.810\, x \approx 0.649\, (x + 20).

Solve for x:

x \approx 81\; \rm ft.

Hence, the height of the top of this tree relative to the base of the hill would be (x + 20)\; {\rm ft}\approx 101\; \rm ft.

6 0
3 years ago
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