The following information about the mean and standard deviation has been provided:
ц=25, б=3,n=20
We need to compute Pr(X⁻≥26.3).
The corresponding z-value needed to be computed is:
![Z=\frac{X-u}{o/\sqrt{n} } =\frac{26.3-25}{3/\sqrt{20} }=1.9379](https://tex.z-dn.net/?f=Z%3D%5Cfrac%7BX-u%7D%7Bo%2F%5Csqrt%7Bn%7D%20%7D%20%3D%5Cfrac%7B26.3-25%7D%7B3%2F%5Csqrt%7B20%7D%20%20%7D%3D1.9379)
Therefor, we get that
![Pr(X\geq 26.3)=Pr(Z\geq \frac{26.3-25}{3/\sqrt{20} } )=Pr(Z\geq 1.9379)\\=1-0.9737=0.026](https://tex.z-dn.net/?f=Pr%28X%5Cgeq%2026.3%29%3DPr%28Z%5Cgeq%20%5Cfrac%7B26.3-25%7D%7B3%2F%5Csqrt%7B20%7D%20%7D%20%29%3DPr%28Z%5Cgeq%201.9379%29%5C%5C%3D1-0.9737%3D0.026)
Answer:
$11.50
Step-by-step explanation:
10(Original cost)*0.15(tip)=1.50
10(Original cost)+1.50(tip)=11.50
Answer:
0.583
Step-by-step explanation:
You have a total of 12 coins in your pockets (3 nickels + 4 dimes + 5 quarters).
There are 7 nickels/dimes (3 + 4), meaning you have a 7/12 chance of picking either a nickel or a dime.
7/12 simplifies to 0.583.
You have a 0.583% chance of picking either a nickel or a dime.
6pints>60 fluid ounces
5quarts= 20cups