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DedPeter [7]
3 years ago
6

being the first grandson, your grand parent decided to give a rectangular field for your coming wedding. If you are given 210 m

wires of fencing, what dimensions would you choose to get the maximum area? a.list all the possible dimensions of the rectangular field b. make a table of values for the possible dimensions c. compute the area for each possible dimension d. what is the maximum area you obtain? e. what are the dimensions of the maximum area you obtained?
Mathematics
1 answer:
Airida [17]3 years ago
5 0

if you are given a certain length of wire the biggest area you can fend up is a circle, 2nd a square.  For the rectangle to have the biggest area,the difference between the 2 sides must be the minimum,  it must approaches a square

 then we have         2(l +w)   =    200

                                  l + w   =     100

the  dimensions   are    49 & 51

multiply    49 by  51  =  2499 sq. m, will give the biggest area, any other      combinations will give a smaller area if you considered decimal numbers between  

<h2 />

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\\ \sf\longmapsto \dfrac{x}{10}=\dfrac{42}{15}

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Answer:

<u><em></em></u>

  • <u><em>a. Meg needs to find the part</em></u>

<u><em></em></u>

  • <u><em>b. Steve needs to find the percent.</em></u>

<u><em></em></u>

Step-by-step explanation:

The question is incomplete.

This is the complete question:

<em>Meg is a veterinarian. In a given week, 50% of the 16 dogs she saw were Boxers. Steve is also a veterinarian. In the same week, 7 of the 35 dogs he saw this week were Boxers. Each wants to record the part the whole, and the percent.</em>

<em />

<em>a. Does Meg need to find the part, the whole, or the percent.</em>

<em />

<em>b. Does Steve need to find the part, the whole, or the percent.</em>

<em />

<h2>Solution to the problem</h2>

<u><em>a. Does Meg need to find the part, the whole, or the percent.</em></u>

<em />

<em>Meg</em> already knows the <em>whole</em> and the <em>percent</em>.

The whole is the entire number of dogs seen: <em>16 dog</em>s.

The percent is <em>50%.</em>

Hence, she needs to find the part: this is how many (what part) of the 16 dogs she saw were boxers.

And she can do with a simple operation:

  • Part = whole × percent = 16 × 50% = 8. This is 8 dogs of 16 were boxers.

<u>b. Does Steve need to find the part, the whole, or the percent.</u>

<u></u>

He already knows <em>the part</em> (<em>7 of the 35 dogs were boxers</em>) and <em>the whole </em>(<em>35 dogs</em>).

Then he needs to find the percent, which he can do using the next operation:

  • Percent = (part / whole) × 100 = (7/35)×100 = 20%
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