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Vladimir [108]
4 years ago
14

Jeffrey earned a gross income of $67,930 last year. He made $2,173.93 in student loan interest deductions, donated $2,824 to his

favorite charities and paid $3,117.56 in home mortgage interest. Jeffrey claims a standard deduction of $11,400 for himself and his non-working spouse. If their exemption is $7,300, what is their taxable income?
a. $47,056.07
b. $52,514.51
c. $43,938.51
d. $41,114.51
Business
1 answer:
LuckyWell [14K]4 years ago
5 0
<span>b. $52,514.51. The $2,173.93 in student loan interest deductions, $2,824 to his favorite charities, and $3,117.56 in home mortgage interest are all tax deductible. However, only $7,300 is exempted from his taxes from the $11,400 they claimed for. Subtracting all this from $67,930, we get $52,514.51.</span>
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Answer:

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Explanation:

Giving the following information:

Io= -$150,000.

The operating costs:

Year 1= $5,000

Year 2= $6,000

Year 3= $7,000

The benefits:

Year 1= $80,000

Year 2= $90,000

Year 3= $70,000

To calculate the Net Present Value (NPV) we need to use the following formula:

NPV= -Io + ∑[Cf/(1+i)^n]

Cf= cash flow

Io= -150,000

Cf1= 80,000 - 5,000= 75,000/1.04= $72,115.39

Cf2= 90,000 - 6,000= 84,000/1.04^2=$77,662.72

Cf3= 70,000 - 7,000= 63,000/1.04^3= $56,006.77

NPV= $31,808.91

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Answer: I think is True

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When goods are produced at the lowest possible cost, an economy is said to have achieved:?
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Answer:

The cost of the equipment is <u>$45,416</u>.

Explanation:

The cost of a newly purchased equipment is the addition of all relevant costs uncured in order to make the equipment ready for use.

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However, any cost incurred to repair any damage to an equipment during installation is not part of equipment cost. Such repair costs are just ordinary expenses that are charged to the income statement during the period.

Based on the explanation above, the cost of the equipment by Oriole Company can be calculated as follows:

Equipment cost = Purchase price + Sales tax + Freight charges + Installation costs ..................... (1)

Since,

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Substituting the values into equation (1), we have:

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