We are the smallest and largest whole numbers that round to 8000 when rounded to the nearest ten thousand

Write a linear function with the values (-1,8) and (5,6)

valentina_108 [34]

Let the function be y = ax + c.

For (-1,8), 8 = a(-1) + c → 8 = - a + c

For (5,6), 6 = a(5) + c → 6 = 5a + c

Subtract one from abother,

2 = - 6a => - 1/3 = a

Hence, 8 = - 1/3 + c → 23/3 = c

Relation is:

y = (-1/3)x + (23/3)

3y = - x + 23

3y = 23 - x

8 0

4 years ago

Can yall pleas help me with this!!!!!!!

Tamiku [17]

Answer:

#5 ∠RST , Obtuse

#6 ∠XYZ, Right

#7 ∠ABC, Straight

#8 ∠HFG, Acute

#9 ∠JPM, Acute

#10 ∠EDF, Right

Hope this helps :)

7 0

3 years ago

Read 2 more answers

Hello I have uploaded the question via image

maksim [4K]

Labour. They are man-made and used in agriculture.

3 0

3 years ago

A development economist is studying income growth in a rural area of a developing country. The last census of the population of

kykrilka [37]

Answer:

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL reject the null hypothesis, so we can say that the population mean is not singificantly higher than 425.

Step-by-step explanation:

Data given and notation

$\bar X=433.75$ represent the mean height for the sample

$\sigma=\sqrt{2500}=50$ represent the population standard deviation for the sample

$n=100$ sample size

$\mu_o =425$ represent the value that we want to test

$\alpha=0.01$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean height actually is higher than the mean height for men in 1960, the system of hypothesis would be:

Null hypothesis: $\mu \leq 425$

Alternative hypothesis: $\mu > 425$

Since we know the population deviation so is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{433.75-425}{\frac{50}{\sqrt{100}}}=1.75$

P-value

Since is a one right tail test the p value would be:

$p_v =P(z>1.75)=1-P(z$

Conclusion

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL reject the null hypothesis, so we can say that the population mean is not singificantly higher than 425.

3 0

4 years ago

Answer this please, thank you !

vesna_86 [32]

Answer:

m∠ADC=55°

Step-by-step explanation:

step 1

Find the value of x

we know that

m∠CDE+m∠EDF=180° ----> by supplementary angles (form a linear pair)

substitute the given values

$(2x+1)\°+(x-7)\°=180\°$

solve for x

$2x+x=180+6$

$3x=186$

$x=62$

step 2

Find the measure of angle ∠ADC

we know that

m∠ADC=m∠EDF ----> by vertical angles

m∠EDF=(x-7)°

substitute the value of x

m∠EDF=(62-7)°=55°

therefore

m∠ADC=55°

8 0

4 years ago