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PtichkaEL [24]
3 years ago
10

The price of a car has been reduced from $14,000 to $8,400. What is the percentage decrease of the price of the car?

Mathematics
1 answer:
Lady bird [3.3K]3 years ago
3 0

Answer: 40%

Step-by-step explanation:

If you divide 8400 by 14000. You will see that $8400 is 60% (.60 in the calculator) you need to subtract that from 100 to find the discount. 100-60= 40

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What is the answer to this question? Please help!
maks197457 [2]

Answer:

B

Step-by-step explanation:

-3\sqrt{2}+3\sqrt{8}= \\\\-3\sqrt{2}+3\sqrt{2\cdot 2^2}= \\\\-3\sqrt{2}+6\sqrt{2}= \\\\3\sqrt{2}

Hope this helps!

6 0
3 years ago
Read 2 more answers
Otis and his 2 brother went to their favorite restaurant. Their total bill was $22.42. They used a coupon for 20% off of the tot
nevsk [136]

Answer:

$ 5.98

Step-by-step explanation:

20/100 × 22.42/1 = $ 4.48

$ 22.42 - $ 4.48 = $ 17.94

If they split that bill in two each would pay $ 5.98

I hope this helps.

4 0
3 years ago
The number of trees in a rainforest decreases each month by 0.5%. The forest currently has 2.5 billion trees. Which expression r
Blababa [14]

Answer:

y=2.5*10^9(0.005^{12 0}) \\\\

Step-by-step explanation:

The above question is in the form of an exponential decay. The equation for an exponential decay is given by:

y=ab^x

where y and x are variables, b < 1, a is the initial value of y (that is the value of y when x = 0).

Let y represent the number of trees left and x represent the number of months. Given that there is currently 2.5 billion trees, therefore a = 2.5 * 10⁹, b = 0.5% = 0.005. The equations becomes:

y=2.5*10^9(0.005^x)\\\\After\ ten\ years(x=10*12\ months=120\ months):\\\\y=2.5*10^9(0.005^{12 0}) \\\\

8 0
3 years ago
Why does (-4 1/2)^2 = 20.25? Thank you please hurry!
AnnZ [28]

Answer:

See below.

Step-by-step explanation:

Squaring a number means to multiply the number by itself.

For example, 3^2 means 3 * 3.

8^2 means 8 * 8.

(-6)^2 means (-6) * (-6).

In each case above, you see that the number that is squared is multiplied by itself.

In this case, (-4.5)^2, squaring the number -4.5, means multiply the number -4.5 by the number -4.5

(-4.5)^2 = (-4.5) * (-4.5)

Now we need to actually multiply -4.5 by -4.5

When you multiply a negative number by a negative number, the result is positive, so the product of -4.5 and -4.5 is a positive number. To find that number, you multiply 4.5 by 4.5

4.5 * 4.5 = 20.25

Therefore, (-4.5)^2 = 20.25

4 0
3 years ago
Experian would like to test the hypothesis that the average credit score for an adult in Virginia is different from the average
aliya0001 [1]

Answer:

a. We fail to reject the hypothesis that the average credit score for an adult in Virginia is different from the average credit score for an adult in North Carolina at the significance level of 0.05.

b. The 95% confidence interval for the true difference of means is -2.2468 and 36.2468. There is a probability of 95% that the true difference of means \mu_{1}-\mu_{2} is between -2.2468 and 36.2468. This confidence interval contains the number 0, this is consistent with the results we got in a. Because we fail to reject the hypothesis that the average credit score for an adult in Virginia is different from the average credit score for an adult in North Carolina at the significance level of 0.05.

Step-by-step explanation:

Let \mu_{1}-\mu_{2} be the true difference between the average credit score for an adult in Virginia and the average credit score for an adult in North Carolina. We have the large sample sizes n_{1} = 40 and n_{2} = 35, the unbiased point estimate for \mu_{1}-\mu_{2} is \bar{x}_{1} - \bar{x}_{2}, i.e., 699-682 = 17.

The standard error is given by \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}, i.e.,

\sqrt{\frac{(44)^{2}}{40}+\frac{(41)^{2}}{35}} = 9.8198.

a. We want to test H_{0}: \mu_{1}-\mu_{2} = 0 vs H_{1}: \mu_{1}-\mu_{2} \neq 0 (two-tailed alternative). The rejection region is given by RR = {z | z < -1.96 or z > 1.96} where -1.96 and 1.96 are the 2.5th and 97.5th quantiles of the standard normal distribution respectively. The test statistic is Z = \frac{\bar{x}_{1} - \bar{x}_{2}-0}{\sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}} and the observed value is z_{0} = \frac{17}{9.8198} = 1.7312. Because 1.7312 does not fall inside RR, we fail to reject the null hypothesis.

b. The endpoints for a 95% confidence interval for \mu_{1}-\mu_{2} is given by 17\pm (z_{0.05/2})9.8198, i.e., 17\pm (z_{0.025})9.8198 where z_{0.025} is the 2.5th quantile of the standard normal distribution, i.e., -1.96, so, we have 17-(1.96)(9.8198) and 17+(1.96)(9.8198), i.e., -2.2468 and 36.2468. There is a probability of 95% that the true difference of means \mu_{1}-\mu_{2} is between -2.2468 and 36.2468. This confidence interval contains the number 0, this is consistent with the results we got in a. Because we fail to reject the hypothesis that the average credit score for an adult in Virginia is different from the average credit score for an adult in North Carolina at the significance level of 0.05.

3 0
3 years ago
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