Jerry drew JKL and MNP so that K= N,L= P, JK=6, and MN=18. Are JKL and MNP similar? IF so, identify the similarity postulate or
theorem that applies.
2 answers:
Answer:
The two considered triangles are similar by the AA rule of similarity.
Step-by-step explanation:
It is given that two triangles that are JKL and MNP are considered in which ∠K= ∠N,∠L= ∠P, JK=6, and MN=18.
Now, from ΔJKL and ΔMNP, we have
∠K= ∠N (Given in the question)
∠L= ∠P(Given in the question)
Thus, by AA rule of similarity,
ΔJKL is similar to ΔMNP.
Thus, the two considered triangles are similar by the AA rule of similarity.
You might be interested in
The first thing to do in this case is to draw the ordered pairs in the Cartesian plane and join the points.
We have then that the resulting figure is a rectangle.
We must find the perimeter of the rectangle that is given by:
P = 2L + 2W
Where,
L: long
W: width
Restoring the values:
P = 2 * (5) + 2 * (3)
P = 16
Answer:
her route cover 16 miles.
We have then that the resulting figure is a rectangle.
We must find the perimeter of the rectangle that is given by:
P = 2L + 2W
Where,
L: long
W: width
Restoring the values:
P = 2 * (5) + 2 * (3)
P = 16
Answer:
her route cover 16 miles.