Jerry drew JKL and MNP so that K= N,L= P, JK=6, and MN=18. Are JKL and MNP similar? IF so, identify the similarity postulate or
theorem that applies.
2 answers:
Answer:
The two considered triangles are similar by the AA rule of similarity.
Step-by-step explanation:
It is given that two triangles that are JKL and MNP are considered in which ∠K= ∠N,∠L= ∠P, JK=6, and MN=18.
Now, from ΔJKL and ΔMNP, we have
∠K= ∠N (Given in the question)
∠L= ∠P(Given in the question)
Thus, by AA rule of similarity,
ΔJKL is similar to ΔMNP.
Thus, the two considered triangles are similar by the AA rule of similarity.
You might be interested in
Answer:
<h2>Step-by-step explanation:
u = kx + ух
First of all factorize x out at the right side of the equation
That's
u = x(k + y)
Divide both sides by ( k + y) to make x stand alone
That's
<h3>We have the final answer as
<h3>Hope this helps you
Answer:
29.5 inches squared
Step-by-step explanation:
The formula for the area of a trapezoid is ,
so base1 = 14 inches and base2 = 30 inches
since there is a right angle, you know that the height must equal the length of the left side, so the height = 15 inches
then, 14+30+15=59 and 59/2=29.5
therefore, your answer would be 29.5 inches squared