The eccentricity of an eclipse is found by using the
formula, eccentricity = c/a
Where,
c represents the distance between the center and a focus.
a represent the distance between that focus and a vertex
The numerical value of the eccentricity of an eclipse ranges
between 0 and 1
Ike scored 382 points.
You do subtraction.
540 - 158
382
29.6+73+33=135.6 180-135.6=44.4
Answer:
y=-3/2x+3
Step-by-step explanation:
The equation for slope intercept form is y=mx+b. The variable m stands for slope, and b stands for the y-intercept.
First, since there's an easy y-intercept to find, we can start from there! The line goes right across the y-axis at 3. 3 is the y-intercept. The equation looks like this now:
y=(?)x+3
Next, find the slope. The easiest way to do this is to look at the points the line goes straight through. These would be (0,3) and (2,0). Slope is written rise over run. If you look at the graph, from the point (2,0), you can find the next point, (0,3), by rising 3 and going over (running) -2, which is actually going backwards. So, as a fraction, the slope is -
.
Another way to find slope is to find two points on the line. We can use the same points we used above again. To find slope with the two points, subtract the y's and then subtract the x's in the same order. Subtract the y's over the x's.
<u>0-3</u>=<u>-3</u> As you can see, we still got the slope as -
.
2-0 2
When we plug in all of the numbers, the equation looks like this: y=-3/2x+3
I hope this helps you out!! Have a great day (*^▽^*)
If you switch it up and multiply one of the equation Ls by 2 it will be easier