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3 years ago

Will mark brainiest

2 answers:

5 0

Ime to walk uphill : t1 = d/3
time to walk downhill: t2 = d/6
total distance = 2d ( up hill and down ill)
2d = (d/3 + d/6)r
2/(1/3 +1/6) = r
r = 4
average speed up and down the hill was 4 mph

total distance = (2/3 x 6 x 4) + (1/3 x 6 x 4)
total distance = 16 + 8 = 24 miles total

Average speed to top of hill = 2/(1/4 +1/3) = 3.43 mph

to top of hill = 24/2 = 12 miles

12 / 3.43 = 3.5 hours
12 oclock + 3.5 hours = 3:30

total miles was 24
arrived at top of hill at 3:30

Sonja [21]3 years ago

3 0

12 oclock to 6 oclock is 6 hours

d = distance
r = rate of speed

time to walk uphill : t1 = d/3
time to walk downhill: t2 = d/6
total distance = 2d ( up hill and down ill)
2d = (d/3 + d/6)r
2/(1/3 +1/6) = r
r = 4
average speed up and down the hill was 4 mph

total distance = (2/3 x 6 x 4) + (1/3 x 6 x 4)
total distance = 16 + 8 = 24 miles total

Average speed to top of hill = 2/(1/4 +1/3) = 3.43 mph

to top of hill = 24/2 = 12 miles

12 / 3.43 = 3.5 hours
12 oclock + 3.5 hours = 3:30

total miles was 24
arrived at top of hill at 3:30

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3 years ago

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Raquel attended a volleyball game that began at 9:30am and ended at 11:45 am she began her lunch at 12:00 pm and ended lunch at

Reil [10]

Answer:

Raquel spend 2 hr 15 Minutes at the volley ball game and 1 hour at the lunch

Step-by-step explanation:

Time Spent at the Volley ball match

The difference of 11:45 and 9 :30 is 2:15 which indicate she spend 2 hour and 15 minutes at the lunch.

sameway , from 12 pm to 1 pm , it encounter a difference of 1 Hour.

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3 years ago

Jane has a circular garden with a diameter of 16 feet if one bag of fertilizer covers 30 ft.² how many bags will she need to cov

AleksAgata [21]

Answer:

She need 7 bags to cover the garden

Step-by-step explanation:

Diameter of circular garden = 16 feet

Radius of circular garden = $\frac{16}{2} = 8 feet$

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30 sq.feet covered by no. of bags = 1

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4 years ago

Find a power series representation of e^x sin(x)

liberstina [14]

The Taylor series is defined by:
$f(x) = \sum \frac{f^n (a)}{n!} (x-a)^n$

Let a = 0.
Then its just a matter of finding derivatives and determining how many terms is needed for the series.

Derivatives can be found using product rule:
$f^n (x) = e^x g^{n-1} (x) + e^x g^n (x) \\ g^0 (x) = sin x$

Do this successively to n = 6.
$f^1 (x) = e^x (sinx +cos x) \\ f^2 (x) = e^x (2cos x) \\ f^3 (x) = e^x(2cos x - 2sin x) \\ f^4 (x) = e^x (-4 sin x) \\ f^5 (x) = e^x(-4sinx -4cos x) \\ f^6(x) = e^x(-8cos x)$

Plug in x=0 and sub into taylor series:
$e^x sin x = x+x^2 +\frac{x^3}{3} -\frac{x^5}{30}-\frac{x^6}{90}...$

If more terms are needed simply continue the recursive derivative formula and add to taylor series.

6 0

3 years ago

A house is listed for sale at $235,000, but the listing does not include square

Galina-37 [17]

Answer:

Option B.

Step-by-step explanation:

If the cost of the house (y) is in thousands and area of the house is x ft².

Cost of the house is modeled by the equation given,

y = 0.06x + 60.5

By substituting the values in the line of best fit,

235 = 0.06x + 60.5

0.06x = 235 - 60.5

0.06x = 174.5

x = $\frac{174.5}{0.06}$

x = 2908.33 ft²

x ≈ 2900 ft²

Therefore, Option B will be the correct answer.

5 0

4 years ago