Question

How many moles of MgS2O3 are in 185 g of the compound?

Answer 1

Answer: The number of moles of $MgS_2O_3$ is 1.36 moles.

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of $MgS_2O_3$ = 185 g

Molar mass of $MgS_2O_3$ = 136.43 g/mol

Putting values in above equation, we get:

$\text{Moles of }MgS_2O_3=\frac{185g}{136.43g/mol}=1.36mol$

Hence, the number of moles of $MgS_2O_3$ is 1.36 moles.

Answer 2

Molar mass MgS2O3 =  136.43 g/mol


185 g x 1 mole MgS2O3 / 136.43 => 1.356 moles

hope this helps!