Answer:
156 g of AlCl₃ will be produced from 3.5 moles of HCl.
Explanation:
Given data:
Number of moles of HCl = 3.5 mol
Grams of AlCl₃ produced = ?
Solution:
Balanced Chemical equation:
3HCl + Al(OH)₃ → AlCl₃ + 3H₂O
Now we will compare the moles of AlCl₃ with HCl from balanced chemical equation.
HCl : AlCl₃
3 : 1
3.5 : 1/3×3.5 = 1.17 mol
Mass of AlCl₃ produced:
Mass = number of moles ×molar mass
Mass = 1.17 mol × 133.341 g/mol
Mass = 156 g
Thus 156 g of AlCl₃ will be produced from 3.5 moles of HCl.
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Answer:
option d.......................