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2 years ago

Someone please help me I’ll give out brainliest please dont answer if you don’t know

Mathematics

1 answer:

DaniilM [7]2 years ago

4 0

Answer:

y = 2x + 5

Step-by-step explanation:

2 is the slope so it goes with the x and 5 is the y-intercept so it is either added or subtracted.

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frutty [35]

Answer:

86.8 what form do u want this answer?

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

What is the slope of a line that passes through the points (12,7) and (-14,19)?

grandymaker [24]

Answer:

H) -6/13

Step-by-step explanation:

To find the slope of the line between a pair of two points, use the slope formula, $m = \frac{y_2-y_1}{x_2-x_1}$ . Substitute the x and y values of (12,7) and (-14,19) into the formula and simplify like so:

$m = \frac{(19)-(7)}{(-14)-(12)} \\m =\frac{19-7}{-14-12} \\m = \frac{12}{-26} \\m = -\frac{6}{13}$

So, Option H is correct.

5 0

2 years ago

Jill simplified the expression shown.

inn [45]

The answer is 3 because 4x-x=3x

8 0

3 years ago

Read 2 more answers

What are the x- and y- coordinates of point P on the directed line segment from K to J such that P is Three-fifths the length of

Mrrafil [7]

Answer:

$\left ( \frac{3x_2+5x_1}{8},\frac{3y_2+5y_1}{8} \right )$

Step-by-step explanation:

Given: P is Three-fifths the length of the line segment from K to J

To find: x- and y-coordinates of point P on the directed line segment from K to J

Solution:

Section formula:

Let point K and J be $(x_1,y_1)\,,\,(x_2,y_2)$ such that the point $p(x,y)$ divides KJ in ratio $m:n$

Then coordinates of point P are given by $\left ( \frac{mx_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n} \right )$

Take $m:n=3:5$

So,

coordinates of point P = $\left ( \frac{3x_2+5x_1}{3+5},\frac{3y_2+5y_1}{3+5} \right )=\left ( \frac{3x_2+5x_1}{8},\frac{3y_2+5y_1}{8} \right )$

7 0

3 years ago

Divid 15 into two parts such that the sum of their reciprocal is 3/10

emmasim [6.3K]

Let x and y be the 2 parts of 15 ==> x + y=15 (given)

Reciprocal of x and y ==> 1/x +1/y ==> 1/x + 1/y = 3/10 (given)

Let's solve 1/x + 1/y = 3/10 . Common denominator = 10.x.y (reduce to same denominator)

==> (10y+10x)/10xy = 3xy/10xy ==> 10x+10y =3xy

But x+y = 15 , then 10x+10y =150 ==> 150=3xy and xy = 50

Now we have the sum S of the 2 parts that is S = 15 and
their Product = xy =50
Let's use the quadratic equation for S and P==> X² -SX +P =0
Or X² - 15X + 50=0, Solve for X & you will find:
The 1st part of 15 is 10 & the 2nd part is 5

4 0

3 years ago